Hä vµ tªn:.........................................
Líp: 8...
§iÓm
§Ò kh¶o s¸t chÊt lîng
M«n: VËt lý. Thêi gian: 30 phót
Lêi nhËn xÐt cña gi¸o viªn
®Ò a
I. PhÇn tr¾c nghiÖm : (3 ®iÓm)
C©u 1: Khi chØ chÞu t¸c dông cña 2 lùc. CÆp lùc nµo sau ®©y lµm vËt ®ang ®øng yªn sÏ
tiÕp tôc ®øng yªn?
A. Hai lùc cïng cêng ®é, cïng ph¬ng.
B. Hai lùc cïng ph¬ng nhng ngîc chiÒu.
C. Hai lùc cïng cêng ®é, cïng ph¬ng, cïng chiÒu.
D. Hai lùc cïng cêng ®é, cïng ph¬ng, ngîc chiÒu.
C©u 2: VËt nh thÕ nµo khi chØ chÞu t¸c dông cña hai lùc c©n b»ng?
A. VËt ®ang ®øng yªn sÏ chuyÔn ®éng nhanh dÇn.
B. VËt ®ang chuyÓn ®éng sÏ dõng l¹i.
C. VËt ®ang ®øng yªn sÏ ®øng yªn, hoÆc vËt ®ang chuyÓn ®éng sÏ chuyÓn ®éng th¼ng
®Òu m·i.
D. VËt ®ang chuyÓn ®éng ®Òu sÏ kh«ng cßn chuyÓn ®éng ®Òu n÷a.
C©u 3: Hµnh kh¸ch ngåi trªn xe « t« ®ang chuyÓn ®éng bçng thÊy m×nh bÞ nghiªng ngêi sang phÝa tr¸i, chøng tá xe:
A. ®ét ngét rÏ sang tr¸i.
B. ®ét ngét rÏ sang ph¶i.
C. ®ét ngét t¨ng tèc ®é.
D. ®ét ngét gi¶m tèc ®é.
C©u 4: Trong trêng hîp lùc xuÊt hiÖn sau ®©y,trêng hîp nµo kh«ng ph¶i lµ lùc ma s¸t?
A. Lùc xuÊt hiÖn khi ta kÐo d·n 1 lß xo.
B. Lùc xuÊt hiÖn lµm mßn ®Õ giµy.
C. Lùc xuÊt hiÖn khi ta ®Èy xe hµng.
D. Lùc xuÊt hiÖn khi ta trît tuyÕt.
C©u 5: Trong c¸c c¸ch lµm sau ®©y, c¸ch nµo lµm gi¶m ®îc lùc ma s¸t?
A. T¨ng lùc Ðp lªn bÒ mÆt tiÕp xóc.
B. T¨ng diÖn tÝch bÒ mÆt tiÕp xóc.
C. T¨ng ®é nh½n gi÷a c¸c bÒ mÆt tiÕp xóc.
D. T¨ng ®é nh¸m cña mÆt tiÕp xóc.
C©u 6: Muèn gi¶m ¸p suÊt ta ph¶i lµm nh thÕ nµo?
A. T¨ng ¸p lùc, gi¶m diÖn tÝch bÞ Ðp.
B. T¨ng ¸p lùc, t¨ng diÖn tÝch bÞ Ðp.
C. Gi¶m ¸p lùc, gi¶m diÖn tÝch bÞ Ðp.
D. Gi¶m ¸p lùc, t¨ng diÖn tÝch bÞ Ðp.
II. PhÇn tù luËn (7 ®iÓm)
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C©u 1: (2,5 ®iÓm) Cho mét qu¶ cÇu ®îc treo trªn sîi d©y(h×nh vÏ)
Hái cã nh÷ng lùc nµo t¸c dông lªn qu¶ cÇu?
H·y biÓu diÔn c¸c vÐc t¬ lùc t¸c dông lªn qu¶ cÇu.
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C©u 2: (1,5 ®iÓm)
Gi¶i thÝch t¹i sao khi nh¶y tõ trªn cao xuèng ch©n ta bÞ gËp l¹i?
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C©u 4: (3 ®iÓm) Mét ngêi cã khèi lîng 45kg ®øng trªn sµn nhµ. BiÕt diÖn tÝch cña 1 bµn
ch©n tiÕp xóc víi mÆt sµn lµ 150cm2. H·y tÝnh ¸p suÊt cña ngêi ®ã t¸c dông lªn mÆt sµn
khi ngêi ®ã:
a) §øng mét ch©n.
b) §øng hai ch©n.
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Hä vµ tªn:.........................................
§Ò kh¶o s¸t chÊt lîng
Líp: 8...
M«n: VËt lý. Thêi gian: 30 phót
§iÓm
Lêi nhËn xÐt cña gi¸o viªn
®Ò b
I. PhÇn tr¾c nghiÖm : (3 ®iÓm) H·y chän ®¸p ¸n ®óng nhÊt
C©u 1: §Æc ®iÓm cña hai lùc c©n b»ng cïng t¸c dông lªn mét vËt lµ:
A. Hai lùc cïng cêng ®é, cïng ph¬ng.
B. Hai lùc cïng ph¬ng nhng ngîc chiÒu.
C. Hai lùc cïng cêng ®é, cïng ph¬ng, ngîc chiÒu.
D. Hai lùc cïng cêng ®é, cïng ph¬ng, cïng chiÒu.
C©u 2: VËt nh thÕ nµo khi chØ chÞu t¸c dông cña hai lùc c©n b»ng?
A. VËt ®ang ®øng yªn sÏ chuyÓn ®éng th¼ng.
B. VËt ®ang chuyÓn ®éng sÏ chuyÓn ®éng sang híng kh¸c.
C. VËt ®ang ®øng yªn sÏ ®øng yªn, hoÆc vËt ®ang chuyÓn ®éng sÏ chuyÓn ®éng th¼ng.
D. VËt ®ang ®øng yªn sÏ ®øng yªn, hoÆc vËt ®ang chuyÓn ®éng sÏ chuyÓn ®éng th¼ng
®Òu m·i.
C©u 3: Hµnh kh¸ch ngåi trªn xe « t« ®ang chuyÓn ®éng bçng thÊy m×nh bÞ nghiªng ngêi sang phÝa ph¶i, chøng tá xe:
A. ®ét ngét rÏ sang ph¶i.
B. ®ét ngét rÏ sang tr¸i.
C. ®ét ngét t¨ng tèc ®é.
D. ®ét ngét gi¶m tèc ®é.
C©u 4: Trong trêng hîp lùc xuÊt hiÖn sau ®©y,trêng hîp nµo kh«ng ph¶i lµ lùc ma s¸t
trît?
A. Lùc xuÊt hiÖn khi ®Èy thïng hµng.
B. Lùc xuÊt hiÖn khi «t« phanh gÊp.
C. Lùc xuÊt hiÖn khi ta ®Èy xe hµng.
D. Lùc xuÊt hiÖn khi ta trît tuyÕt.
C©u 5: Trong c¸c c¸ch lµm sau ®©y, c¸ch nµo lµm t¨ng ®îc lùc ma s¸t?
A. T¨ng ®é nh¸m cña mÆt tiÕp xóc.
B. T¨ng diÖn tÝch bÒ mÆt tiÕp xóc.
C. T¨ng ®é nh½n gi÷a c¸c bÒ mÆt tiÕp xóc.
D. T¨ng lùc Ðp lªn bÒ mÆt tiÕp xóc.
C©u 6: Muèn t¨ng ¸p suÊt ta ph¶i lµm nh thÕ nµo?
A. T¨ng ¸p lùc, gi¶m diÖn tÝch bÞ Ðp.
B. T¨ng ¸p lùc, t¨ng diÖn tÝch bÞ Ðp.
C. Gi¶m ¸p lùc, gi¶m diÖn tÝch bÞ Ðp.
D. Gi¶m ¸p lùc, t¨ng diÖn tÝch bÞ Ðp.
II. PhÇn tù luËn (7 ®iÓm)
C©u 1: (2,5 ®iÓm) Cho mét cuèn s¸ch ®Æt trªn bµn (h×nh vÏ)
Hái cã nh÷ng lùc nµo t¸c dông lªn cuèn s¸ch?
H·y biÓu diÔn c¸c vÐc t¬ lùc t¸c dông lªn cuèn s¸ch.
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C©u 2: (1,5 ®iÓm)
Gi¶i thÝch t¹i sao khi c¸n bóa láng, cã thÓ lµm chÆt c¸n bóa b»ng c¸ch gâ m¹nh ®u«i
c¸n xuèng ®Êt?
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C©u 4: (3 ®iÓm) Mét ngêi cã khèi lîng 60kg ®øng trªn sµn nhµ. BiÕt diÖn tÝch cña 1 bµn
ch©n tiÕp xóc víi mÆt sµn lµ 200cm2. H·y tÝnh ¸p suÊt cña ngêi ®ã t¸c dông lªn mÆt sµn
khi ngêi ®ã:
c) §øng mét ch©n.
d) §øng hai ch©n.
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®¸p ¸n ®Ò kh¶o s¸t chÊt lîng
®Ò a
I. phÇn tr¾c nghiÖm:
Mçi c©u tr¶ lêi ®óng ®¹t 0,5 ®iÓm
C©u
1
2
3
4
5
6
§¸p ¸n
D
C
B
A
C
D
ii.phÇn tù luËn:
C©u 1:
- Gåm hai lùc t¸c dông lªn qu¶ cÇu: Träng lùc vµ lùc c¨ng cña sîi d©y.
(1®)
- BiÓu diÔn lùc ®óng nh h×nh vÏ
(1,5 ®)
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T
A
C©u 2: (1,5 ®)
P
Khi nh¶y tõ trªn cao xuèng, ch©n ch¹m ®Êt bÞ dõng ngay l¹i, nhng ngêi vÉn cßn chuyÓn
®éng vÒ phÝa díi theo qu¸n tÝnh nªn lµm ch©n gËp l¹i.
C©u 3:
Tãm t¾t: m= 45kg; S1 = 150cm2=0,015m2; S2=2.S1=0,03m2
P1=?
P2=?
(0,5 ®)
Gi¶i:
¸p lùc cña ngêi ®ã lªn sµn nhµ lµ: F= 10.m = 10.45 = 450 (N) (0,5 ®)
¸p suÊt cña ngêi ®ã khi ®øng 1 ch©n lµ:
P1 = F/ S1 = 450/0,015 = 30 000 (Pa)
(1 ®)
¸p suÊt cña ngêi ®ã khi ®øng 2 ch©n lµ:
P2 = F/ S2 = 450/0,03 = 15 000 (Pa)
(1 ®)
§¸p sè:
®¸p ¸n ®Ò kh¶o s¸t chÊt lîng
®Ò b
I. phÇn tr¾c nghiÖm:
Mçi c©u tr¶ lêi ®óng ®¹t 0,5 ®iÓm
C©u
1
2
3
4
§¸p ¸n
C
D
B
C
5
A
6
A
ii.phÇn tù luËn:
C©u 1:
- Gåm hai lùc t¸c dông lªn cuèn s¸ch: Träng lùc vµ lùc n©ng cña mÆt bµn.
- BiÓu diÔn lùc ®óng nh h×nh vÏ
(1,5 ®)
(1®)
A N
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C©u 2: (1,5 ®)
P
Khi gâ m¹nh ®u«i c¸n bóa xuèng ®Êt, c¸n bóa ®ét ngét bÞ dõng l¹i, nhng ®Çu bóa vÉn
tiÕp tôc chuyÓn ®éng xuèng phÝa díi do cã qu¸n tÝnh, nªn ®Çu bóa ngËp chÆt vµo c¸n
bóa.
C©u 3:
Tãm t¾t: m= 60kg; S1 = 200cm2=0,02m2; S2=2.S1=0,04m2
P1=?
P2=?
(0,5 ®)
Gi¶i:
¸p lùc cña ngêi ®ã lªn sµn nhµ lµ: F= 10.m = 10.60 = 600 (N) (0,5 ®)
¸p suÊt cña ngêi ®ã khi ®øng 1 ch©n lµ:
P1 = F/ S1 = 600/0,02 = 30 000 (Pa)
(1 ®)
¸p suÊt cña ngêi ®ã khi ®øng 2 ch©n lµ:
P2 = F/ S2 = 600/0,04 = 15 000 (Pa)
(1 ®)
§¸p sè:
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