Tài liệu Luyenchonnhanhdapanbaitaptracnghiemhoahoc12

L5X7C N G U Y E N HlTU T H A C LUYEN CHON NHANH DAP AN BAI TAP TRAC NGHIEM H O A H O C 12 nAi NHA X U A T BAN H A NOI Chiu track nhiem xudt ban N G U Y f i N K I M SON Chiu trdch nhiem noi dung vd bdn quyin TRUNG T A M V A N HOA TRANG A N Bien tap noi dung PHAM Q U O C T U A N Trinh bay bia PHAM HUE duiL Theo chii trirong cua Bo Giao due va Dao tao, trong nhirng nam hoc vCra qua viec danh gia ket qua hoc tap, cung nhir trong cac k i thi tuyen sinh, phuofng thiic thi trdc nghiem da dugc sir dung rpng rai. De giiip cac em hoc sinh thanh thao va lam t6't cac bai tap theo phuong thiic nay, chiing toi bien soan cuon sach Luyen chqn nhanh dap an bdi tap trdc nghiem Hoa hoc 12 dung de on luyen thi td't nghiep THPT va thi Dai hoc, Cao dang. Noi dung cuon sach gom hai phan: Phan I : B A I T A P T R A C N G H I E M Cac bai tap trac nghiem trong phan nay dugc bitn soan theo tCrng chuang ciia SGK (ca ban va nang cao). M 6 i bai tap c6 bon dap an tra 16i ( A , B, C, D)," ban doc se chpn lay mot dap an diing. Phan H : H U O N G DAN T R A LC)I Phan nay dugc trinh bay rat ngan gon, hudng dan ban doc each t l m dap an diing, nhanh nha't va chinh xac nhat (khong cSn phai giai cu the nhu lam bai tap ta luan). LUYfiN C H O N NHANH D A P A N B A I T A P T R A C N G H l f i M H O A H O C 12 In 1000 cuon, kh6 16x24cm, tai X i nghiep in N X B Van hoa Dan t6c Dang k i K H X B so: 451 -2013/CXB/30c T K - 43/HN In xong va nop liai chieu nam 2013 Ban doc c6 the diing phan nay de tir kiem tra, danh gia ket qua hoc tap ciia minh. Qua do vCra ciing c6 dugc kien thiic, vira hgc dugc each lam tdt nha't m6t bai tap trac nghiem. Cuon sach Luyen chpn nhanh dap an bdi tap trdc nghiem Hoa hoc 12 dugc tai ban Ian thii hai nay c6 chinh l i va bo sung. Xin dugc gidi thieu vdi cac em hgc sinh cung cac vi phu huynh va thiy c6 giao. TAC GIA Phan I BAI T A P T R A C N G H I E M Chuang 1 €ST€ - U P I T 1.1. Phan Crng tirong tac cua axit v 6 i ancoI tao thJlnh este, dircrc g o i 1^ : A . Phan ling trung hoa. B. Phan ling ngung t u . C. Phan ling este hoa. D. Phan ij:ng kd't hop. Hay chon dap an dung. 1.2. Thiiy phan este trong m 6 i tru&ng k i l m dun n6ng g o i la : A . Xa phong hoa ; B. H i d r a t h6a ; C. Crackinh ; D . Sir Idn men. Hay chon dap an diing. 1.3. Thuy phan este trong m 6 i trudng k i d m , thu ducfc : A . Mu6'i va nude ; B. M u 6 i vel a n c o l ; C. A n c o l va nu6c ; D . A x i t vk ancol. } ae<::'. , Hay chon dap an dung. 1.4. Cap axit nao sau day duoc g o i la axit b6o ? A . A x i t stearic va axit fomic. B. A x i t oleic va axit fomic. C. A x i t panmitic va axit glutamic. D . A x i t panmitic va axit stearic. i k ,6 r . 5 1.5. Chat beo CO CTPT (CnHjgCOOgCgHg CO ten ggi : 1.6. A. Glixerol tristearat. B. Propin tristearat. C. Glixerol stearat. D Triglixerol stearat ; Hay chon ttn gpi diing. Trong cac cau sau day, cau dung nha't la : A. Dau an la h6n hop nhi6u este. 1.7. B. Dau an la este cua glixerol. C. Dau an la este cua glixerol va axit beo. D. D&u an la este. Hay chpn dap an dung. M5 tir nhien la : A. Este ciia axit panmitic (CJ5H31COOH). B. Mu6'i cua axit beo. C. H6n hgp ciia cac loai lipit khac nhau. D. Este cua axit oleic (CiyHjjCOOH). Hay chon dap an dung. 1.8. San ph^m hidro hoa triglixerit cua axit cacboxylic kh6ng no goi la: A. M6 h6a hoc. B. Dau thuc vat. C. Macgarin (diu thirc vat bi hidro hoa). D. Mo thirc vat. Hay chon dap an dung. 1.9. C6ng thiic tdng quat nao sau day la cLia este don chirc ? A. H R - C - R ' H . M o B. R - C - O - R ' . II O C. R-CH2-O-O-R'. D. R-O-CH2 -0-R'. 1.10. Mu6'i ciaa axit beo dirge gpi la: A. Mufi'i hifu CO ; B. Este ; C. Mo ; D. Xa phong. Hay chon dap an dung. •1.11. Xa ph6ng dugc san xua't bang cdch nao dirdi day ? A. Phan hijy dSu, mo. B. Thijy phan mo bang kiem. C. Phan iJng axit vdri kim loai. D. hidro h6a mo tu nhien. 1.12. Thanh ph^n chii ye'u ciia nhidu loai b6t giat tdng hgp la : -J o A. Este ciia axit beo. , ,. . , B. Dan xua't ciia xenlulozo. . C. Ankyl sunfat. D. Xa phong nhan tao. Hay chgn dap an diing. 1.13. Phuong phap nao la dung nha't d^ lam sach quSn ao dinh ve't diu an ? A. Giat bang nirdrc. B. Giat bang c6n ; C. Giat bang xa phong. D. Giat dy bang xang. A. • 7 1.14. Cho 60 gam axit axetic tac dung vori 100 gam ancol etylic, thu diroc 55 gam este. Hi6u sua't phan ling tren la : A. 62,5% ; B. 55% ; C. 21,7% ; D. 58%. Hay chon ddp s6' dung. 1.15. Thuy phan cha't beo glixerol tristearat (C]7H35COO)3C3H5 phai dung 1,2 kg NaOH. Gi^ sir hi6u sua't 80%. Kh6'i luang glixerol thu duoc la : A. 9,2 kg; B. 0,736 kg ; C. 0,92 kg ; D. 7,36 kg. Hay chpn dap an dung. 1.16. Dot chay hoan toan m6t lugng h6n hgp 2 este, cho san pham phan irng chay qua binh dirng P2O5 du, khoi lugng binh tang 6,21 gam, sau do cho qua tiep binh dirng Ca(0H)2 du, thu dugc 34,5 gam ket tua. Cac este noi tren thu6c loai gi ? (dan chirc hay da chirc, no hay khong no). A. Este thu6c loai no. B. Este thu6c loai kh6ng no. C. Este thu6c loai no, dan chirc. • D. Este thuOc loai khdng no, da chiic. Hay chon dap an diing. 1.17. E la este ciia m6t axit dan chiic va ancol dan chu-c. De' thuy phan hoan toan 6,6 gam chat E phai dung 34,10 ml dung dich NaOH 10% (D = 1,1 gam/ml). Lugng NaOH nay du 25% so v6i lugng NaOH phan irng C6ng thurc ca'u tao ciia E la : 8 A. CH3COOCH3. B. HCOOC3H7; C. CH3COOC2H5. D. Ca hai cau B va C deu diing. Hay chon c6ng thiic diing. 1.18. M6t hgp chat hifu ca X c6 CTPT C7H12O4. Biet X chi c6 mfit loai nhom chiifc. Khi cho 16 gam X tac dung vira dii vdi 200 gam dung dich NaOH 4%, thu dugc 1 ancol Y va 17,8 gam h6n hgp hai mu6'i. , C6ng thicc cS'u tao thu ggn ciia X la : A. CH3OOC-COOC2H5; B. CH3COO - (CH2 )3 - OOC2H5; ^ C. C H 3 C O O - ( C H 2 ) 2 - O O C 2 H g ; H- D. Tat ca deu sai. Hay chon cong thirc dung. 1.19. H6n hgp X gom hai este dan chiJc, d6ng phan ciia nhau. D6t chay a gam X, thu dugc 6,72 lit CO2 va 5,4 gam H2O. Cong thirc phan tir ciia hai este dan chd-c d6ng phan c6 dang : A. C „ H 2 n 0 2 (n > 2). B. CnH2n-202 (n> C. C„H2n-202 ^ 1). (n>3). . D. C„H2n-402 ( n > 2 ) . Hay chon cong thtirc diing. 1.20. Cho 21,8 gam chat hiru ca A chi chiia m6t nhom chile tac dung v6i 1 lit dung dich NaOH 0,5M thu dugc 24,6 gam mud'i va 0,1 mol ancol B. Lugng NaOH du c6 the trung hoa he't 0,5 lit dung dich HCl 0,4M. Cho biet c6ng thirc ca'u tao thu ggn ciia A : A. (CH3COO)3C3H5. B. (HCOO)3C3H5. ) C. (C2H5COO)3C3H5. 51, ^ D. K^t qua khac. Hay chon cong thurc diing. i .A 9 1.21. X 1^ h6n hap cua hai este d6ng phan v6i nhau. C) cQng diiu k\tn nhiet da va ap sua't, 1 lit hoi X nang ga'n 9 lin 1 lit khi CO2 . Thuy phan 35,2 gam X bang 4 1ft dung dich NaOH 0,2M dirac dung djch Y. C6 can Y dircfc 44,6 gam cha't ran khan. Bid't hai este do ancol no don chirc axit no don chiic tao thanh. C6ng thiic phan tir ciia hai este : A. B. C2H4O2; C. C 4 H 8 O 2 ; Hay chpn c6ng thiJc dung. 1.22. C3H6O2; D. CgHioOz. hop Y g6m hai este don chiic mach ho la d6ng phan cua nhau. Cho m gam h6n hop Y tac dung vira dij v6i 100 ml dung NaOH 0,5M, thu diroc mot muoi cua m6t axit cacbonxylic va h6n hop hai ancol.Mat khac d6t chay hoan toan m gam h6n hop Y cdn dung 5,6 lit O2 va thu dirge 4,48 lit CO2 (c^c th^ tich do cf di^u kifin tidu chu^n). C6ng thiJc ca'u tao ciia hai este trong h6n hop Y la : A. CH3COOCH3 va HCOOC2H5 . C 2 H 5 C O O C H 3 va C. C H 3 C O O C H 3 va D. HCOOCH2 - CH2 - C H 3 HCOOC3H7 CH3COOC2H5. va HCOO - CH 'CH. CH3. Hay chon cong thiJc dung. 1.23. D6't chay hoan toan 6 gam este E, thu dugc 4,48 lit CO2 (dktc) va 3,6 gam H2O. C6ng thiic phan tir ciia este E 1^ : A. C4H6O4 ; B. C4H6O2 ; C. C3H6O2 ; D. C2H4O2. Hay chon cong thiic diing. 1.24. M6t este don chiic, mach h6 c6 kh6'i lugng la 12,9 gam tac dung \i[a dii v6i 150 ml dung djch KOH IM. Sau phan iJng thu dugc mu6'i vk andehit. Cong thurc ca'u tao nao dudri day la ciia este ? A. HCOOCH = C H - C H 3 . 10 A. C6H,202 ; C. CsHioOs; H6n B. B. CH3COOCH = CH2 • C. C2H5COOCH = CH2. D. HCOOCH = CH - C H 3 va C H 3 C O O C H = CHj . 1.25. Di xa phong hoa 17,4 gam m6t este no dan chiJc, c^n d&ng 300 ml dung dich NaOH 0,5M . C6ng thiic phan tir ciia este la : C3H6O2 ; A D. C 4 H , o 0 2 . ) B. Hay chon cong thiic dung. 1.26. Cho h6n hop X g6m 2 este c6 c6ng thiic phan tir C 4 H 8 O 2 va C 3 H 6 O 2 ' tac dung vai NaOH dir thu dugc 6,14 gam h6n hop hai mu6'i v^ 3,68 gam ancol B duy nha't c6 ti kh6'i so v6i oxi la 1,4375. KhO'i lugng m6i este trong X iSn lugt la : A. 2,22 gam va 4,4 gam. B. 3,33 gam va 6,6 gam. ' C. 4,44 gam va 8,8 gam. D. 5,6 gam va 11,2 gam. Hay chon dap an dung. ' ''"^ '^^'^ 1.27. X la h6n hgp 2 este dong phan dugc tao thanh tir m6t ancol dan chiJc, mach cacbon khong phan nhanh v6i axit don chiifc. Ti kh6'i hoi cua X so v6i H2 bang 44. Cong thiic phan tir cua X la : A. C3H6O2 ; C. C5H,o02; B. D. C4H8O2 ; ^ C6H12O2. Hay chon c6ng thiic diing. 1.28. Trong m6t binh kin dung tich khong ddi la V lit chiJa hoi cha't huu ca X mach ho va O2 a 139°C; ap sua't trong binh la 2,71 atm (th6 tich O2 ga'p doi the tich cin cho phan ung chay). Dot chay hoan toan X luc do nhiet d6 trong binh la 819 K va ap sua't la 6,38 atm. Bie't phan tu X c6 dang C n H 2 n 0 2 • Cong thiic phan tir ciia X la : 11 1.29. A. C4H8O2 ; B. C3H6O2; C. C2H4O2 ; D. C2H3O2 . tirciia 2 este la : Hay chon c6ng thirc diing. A. HCOOC2H5 va CH3COOCH3. D6't chay hoan loan 0,88 gam h6n hgp 2 este d6ng phan, thu dugc B. C2H5COOCH3 va CH3COOCH3. 1,76 gam CO2 va 0,72 gam H2O . C6ng thiJc phan tir cua 2 este la : C. CH3COOC2H5 va HCOOC3H7. A. C3H6O2 ; B. C2H4O2 ; D. Kh6ng x^c dinh dirge. C. C4H6O2; D. CsHioOj. Hay chon c6ng thiic diing. Hay chon c6ng thiJc diing. 1.30. n6i tren phai diing vCra he't 12 gam NaOH nguyen cha't. C6ng thii-c phan 1.33. bang NaOH nguyen chat. Khfi'i lugng NaOH da phan irng la : D6't chay hSt h6n hgp 2 este no, don chiJc, thu du'gc 1,8 gam H2O . Thuy phan hoan toan h6n hgp 2 este tren, thu dugc h6n hgp X gom ancol va axit. Ne'u dot chay 1/2 h6n hgp X thi the tich khi CO2 thu dugc (dktc) la : A. 2,24 lit ; B. 3,36 lit ; C. 1,12 l i t ; D. 4,48 lit. A. 8 gam ; B. 12 gam ; C. 16 gam ; ' D. 20 gam. Hay chgn dap s6' dung. 1.34. Xa phong hoa 22,2g h6n hgp 2 este laHCOOC2H5 va CH3COOCH3 bang lugng dung dich NaOH \iia dii, cic mu6\h ra sau khi xa phong hoa dugc sa'y den khan va can dugc 21,8 gam. S6' mol HCOOC2H5 va Hay chon dap s6' dung. 1.31. Xa phong hoa 22,2g h6n hgp 2 este laHCOOC2H5 va CH3COOCH3 CH3COOCH3 lin lugt Ik : Khi xa phong hoa 2,18 gam Z c6 c6ng thirc phan tir la C 9 H 1 4 O 6 , da A. 0,15 mol va 0,15 mol. dung 40 ml dung dich NaOH I M . Di trung hoa Urgng xiit dir sau phan ung xa phong hoa phai dung het 20 ml dung djch HCl 0,5M. Sau phan B. 0,2 mol va 0,1 mol. ung xa phong hoa ngudi ta nhan dirge ancol no B va mu6'i natri cira axit C. 0,25 mol va 0,05 mol. hiru CO m6t lin axit. Biet rang 11,50 gam B a the hoi chiem the' tich D. 0,275 mol va 0,005 mol. . bang the tich cua 3,75 gam etan (do a cung nhiet d6 va ap sua't). Cho Hay chgn dap s6' diing. cac phan iirng xay ra hoan toan. Tim c6ng thiic ca'u tao cua ancol B. A. C2H4(OH)2 ; B. C3H5(OH)3 ; C. C3H6(OH)2 ; D. C4H7(OH)3. 1.35. Co 2 este c6 d6ng phan ciia nhau va deu do cac axit no don chCrc va ancol no don chiJc tao thanh. De xa phong hoa 22,2 gam h6n hgp 2 este Trong moi trudng kiem , phenol lie dung dugc vdi chat nao sau day d^ tao thanh este phenyl axetat ? Hay chon c6ng thiJc diing. 1.32. 1.36. A. C H 3 C O O H ; B. (CH3CO) 2O ; C. C H 3 C H O ; D- CH3C00Na. Trieste ciia glixerol v6i cdc axit cacboxylic don chirc, mach cacbon dai, kh6ng phan nhanh ggi 1^ : 12 ' " " "' A. Lipit ; B. Protein ; C. Gluxit ; D. Polieste. Hay chon dap an diing. 1.37. S6 ddng phan este irng v6i c6ng thirc phan tir C3H(502 la bao nhieu ? A. 4 d6ng phan ; B. 5 d6ng phan ; C. 2 ddng phan ; D. 3 d6ng phan. 1.38. Glixerol va axit beo stearic c6 the tao duac t6'i da bao nhieu dang este? A. 2 dang este ; B. 3 dang este ; C. 5 dang este ; D. 4 dang este. 1.39. Co bao nhieu trieste glixerol chiJa ddng th5i 3 goc ciia cac axit CnHjsCOOH, CiyHgjCOOH va CjsHjiCOOH ? A. 2 trieste ; B. 3 trieste ; C. 4 trieste ; D. 5 trieste. 1.40. Cho glixerol tac dung \di h6n hop 3 g6'c axit beo C17H35COOH, C17H33COOH va C,5H3,COOH. S6 dang trieste toi da c6 the duac tao thanh la : A.,9 dang trieste ; " B. 16 dang trieste ; C. 12 dang trieste ; D. 18 dang trieste. Hay chon dap an diing. 1.41. Thuy phan hap chat C4H6O2 trong m6i tru6ng axit, thu dugc h6n hop hai chat d6u c6 kha nang tham gia phan ling trang guang. C6ng thirc ca'u tao ciia hap cha't do la : A. CH3-COO-CH = CH2. B. H - C O O - C H 2 - C H = CH2. C. H - C 0 0 - C H = CH-CH3. D. C H 2 = C H - C O O - C H 3 . Hay chon c6ng thiic diing. 14 1.42. Thuy phan este E c6 c6ng thiJc phan tir C4H8O2 v6i xiic tic axit v6 ca loang, thu dirge hai san ph^m hiru ca X va Y. Tir X c6 th^ dieu che' ra trirc tiep ra Y bang m6t phan umg duy nha't. X c6 c6ng thiic ca'u tao : A. CH3COOH. B. C2H5OH. C. C H 3 - C H 2 - C O O H . Ti- D. C H 3 - C O O - C 2 H 5 . Hay chon c6ng thiJc diing. 1.43. CnH2n02 CO i the la c6ng thiic tdng qudt ciia loai hgp cha't iiao dudi day? A. Axit cacboxylic no, dan chiic, mach ha. B. Este kh6ng no (c6 m6t lien ke't dOi), dan chiic. C. Andehit. D. Ancol no, hai chCrc, mach hb. 1.44. Di^u che' etyl axetat tir etilen cfin thuc hien tS'i thi^u bao nhidu phan umg ? . A. 5 phan iJng ; B. 4 phan ling ; C. 3 Phan ilng ; ' D. 2 Phan ling. 1.45. Ten goi cua este c6 mach cacbon kh6ng phan nhanh c6 c6ng thiic phan tir C4H8O2 CO the tham gia phan ling trang guang la : -f^ > < « ' ^ A. Propyl fomiat. -fi^ " B. Isopropyl fomiat. C. Etyl axetat. D. Metyl propionat. Hay chon ten goi diing. ' -* 1.46. Este dugc tao bai ancol thu6c day ddng dang ciia ancol etylic va axit thu6c day ddng dang axit axetic c6 c6ng thiic chung la : 1.50. Cho 7,4 gam este X no, don chufc phan img v6i dung dich AgNO^/NH, dir, thu dugc 21,6 gam ke't tua. COng thiic ca'u tao ciia X la : A.C„H2n02 ( n > 2 ) . BC„H2n+,02(n>3). C.C„H2n.,02(n>2). A. H - C O O - C H 3 . D- CnH2n.202 (n > 3) ; B. H - C O O - C H 2 - C H 2 - C H 3 . Hay chgn c6ng thirc diing. 1.47. Hai hgp chat hOu co ( chiia C, H, O) c6 so mol bang nhau va bang X mol. Cho Chung tac dung vilra du v6i nhau tao ra san ph^m A kh6ng tan trong n\xdc va c6 kh6'i lirgng nho hon tdng khdi lirgng cua hai hgp cha't ddu la 18x gam. A thugc loai hgp chat : A. Axit ; C. MuO'i ; Hay chgn dap an diing. C. H - C O O - C 2 H 5 . D. H - C O O - C H ( C H 3 ) C H 3 . Hay chgn c6ng thiJc dung. 1.51. Dot chay hoan toan 0,1 mol este X roi dSn san pham chay vao dung dich Ca(OH)2 du, thu dugc 20 gam ke't tua. C6ng iMc phan tir ciia X la : B. Ancol ; D. Este. . A A. H - C O O - C H 3 . B. C H 3 - C O O - C H 3 . 1.48. Este E c6 cOng thirc phan tijrC5H|o02 . Xa phong hoa E, thu dugc mfit ancol khOng bi oxi hoa bdi CuO. Ten cua E la : A. Isopropyl axetat. B. Tertbutyl fomiat. C. Isobutyl fomiat. D. Propyl axetat. Hay chgn tfin ggi dung. 1.49. Thirc hifin phan ling este h6a m gam C H 3 C O O H bang m6t lugng vCra dii C2H5OH, thu dugc 0,02 mol este (hieu sua't phan ling 100%). Gia trj ciia m la : A. 2,1 gam ; C. 1,2 gam ; Hay chgn dap s6' diing. ' B. 1,1 gam ; D. 1,4 gam. C. H - C O O - C 2 H 5 . D. C H 3 - C O O - C 2 H 5 . ' ^• Hay chgn c6ng thiic dung. ' ; > 1.52. Xa phong hoa 2,22 gam hai h6n hgp este A, B d6ng phan ciia nhau cfin diing het 30 ml dung dich NaOH IM. Mat khac khi d6't chay hoan toan h6n hop este d6 thu dugc khf CO2 va H2O v6i th^ tich bang nhau (0 Cling dieu kifn). C6ng thiic ca'u tao cua hai este la : I A. CH3COOCH3 va HCOOCjHg. B. CH3COOC2H5 vk C2H5COOCH3. C. HCOOCH2CH2CH3 va HCOOCH(CH3)CH3. j D. C H 3 C O O C H = CH2 va CH2 - CHCOOCH3 . I Hay chgn c6ng thiic diing. , Y z — \ i.i / ^ % \ 17 1.53. D6t chiy hokn loan a gam h6n hgp cac este no, don chtrc, mach hor. San 1 58. pham chay dugc dan vao binh dirng dung dich Ca(OH)2 dir tha'y kho'i va axit khong no (c6 mot lien ket dOi) dan chiic, mach ho,'thu dUv^c lugng binh tang 1,24 gam. Kh6'i lugng ke't tua tao ra la : 4,48 l i t k h i C O 2 (dktc) va 1,8 gam H 2 O . A. 12,4 gam ; C. 20 g a m ; B. 10 gam ; Gia t r i cua a la : . . D. 28,183 gam. Hay chgn dap s6' diing. 1.54. Dot chay hoan toan a m o l este X tao boi ancol no, don chiic, mach ho 1.59. lirgng binh tang 6,2 gam. S6' m o l C O j va H 2 O sinh ra iSn lugt la : A. 0,1 va 0,1 ; C . 0,1 v a 0 , 0 1 ; B. 0,05 m o l ; B. 0,1 m o l ; C. 0,15 m o l ; D. 0,20 m o l . Hay chgn dap s6' diing. D6't chay hoan loan a gam h6n hgp cac este no, don chiJc, mach ho. San ph^m chay dugc dSn vao binh dirng dung dich nude v6i trong tha'y k h 6 i A. Dot chay hoan toan 6 gam este X , thu dugc 4,48 l i t COj (dktc) va 3,6 gam H j O . C6ng thiJc phan tir cua X la : 0,01 va 0,1 ; D. 0,01 vaO,01. • A.CSHKPS; B. C4H8O2; C. C 3 H 6 O 2 ; D. C 2 H 4 O 2 . Hay chgn dap s6' dung. Hay chgn c6ng thiic dung. 1.55. K h i dg't chay hoan toan este X cho n^o^ = n^^Q. Di thuy phan hoan toan 0,6 gam este X cSn dung d i c h chiia 0,1 m o l N a O H . C6ng thirc 1.60. 0,45 m o l H 2 O . C6ng thiic phan tir cua este la : phan t u cua este la : A . C2H4O2 ; B. C 3 H 6 O 2 ; C. C 4 H 8 O 2 ; D. C 5 H , o 0 2 . A . C2H4O2 ; Hay chgn cSng thiJc dung. 1.56. D6't chay hoan toan 0,1 m o l este X thu dugc 0,3 m o l C O j va 0,3 m o l Dot chay hoan toan 0,15 m o l este X , thu dugc 19,8 gam C O 2 >a 1.61. C. C 4 H 8 O 2 ; I D. C5H10O2. Hay chon cong thiic dung. •^-.-^liVm H> .F ' De trung hoa 140 gam m6t chat beo cin • V, ^ A, • 15 m l dung dich K O H I M . Chi s6' axit cua chat beo bang : H 2 O . Ne'u cho 0,1 m o l X tac dung he't vdri N a O H t h i thu dugc 8,2 gam m u 6 i . C6ng thiic ca'u tao cua X la : A. 5; A. HCOOC2H3 ; B. C H 3 C O O C H 3 ; C 7 • C. H C O O C 2 H 5 ; D. C H 3 C O O C 2 H 5 . Hay chgn dap an dung. 1.62. Hay chgn c6ng thiic dung. B. C 3 H 6 O 2 ; B.6; D. 8. ffq'^ K h i xa phong hoa 7,5 gam cha't beo cSn 100 m l dung dich K O H I M . C h i s6' xa phong hoa cua cha't beo la : 1.57. D6't chdy m6t este no, don chirc, mach ho thu dugc 1,8 gam H 2 O . T h ^ tich C O 2 (dktc) thu dugc la bao nhieu ? A . 2,24 l i t ; B. 4,48 l i t ; C-3,36 l i t ; D. 1,12 l i t . A . 373,33; ^ ^. ^ B. 0,3733 ; C . 3,733 ; ^ Hay chgn dap an diing. \ 'V. .^.,„;„>«i'^v:^ D. 37,333. • \ 19 1.63. Chat b6o X c6 chi s6' axit bang 7. S6 gam NaOH c^n b6o CO trong 5 kg chat beo X la : A. 35 gam ; B. 40 gam ; C. 42,2 g a m ; D. 45,8 gam. Hay chon ddp s6' diing. trung h6a axit ' • 1.64. De xa phong hoa 10 kg chat beo (RCOO)3C3H\c 1.75. Este X CO cdng thirc phan tir CgH804. Khi tac dung vdi dung dich NaOH, thu dupe mdt mud'i va 2 ancol. t' , ' Cdng thiirc ca'u tao ciia X la : J« i A. C H 3 - O O C - C H 2 - C O O - C H 3 . . B. CH3 - OOC - COO - C3H7. y I :: C. C H 3 - O O C - C O O - C H 2 - C H 3 . ; ,. D. Ca A, B, C d^u diing. Hay chon cdng thiic dung. ' ' *^ 23 1.76. PhSn 2 cho tdc dung vdi 3 0 gam CH3COOH (c6 H2SO4 dac xiic tac) . Este X C O c6ng thirc phan tir C<;H804 khi tac dung v6i dung dich NaOH, thu ducrc 2 muoi va 1 ancol. Hieu sua't ciia phan urng este hoa d^u la 8 0 % . C6ng thirc ca'u tao cua X la : Tdng kh6i lugng este thu dugc la : A. C H 3 - O O C - C H 2 - C O O C H 3 . B. H - OOC - CH2 - CH2 - COOCH3 . C. C H 3 - C O O - C H 2 - C H 2 - O O C - H . 1.77. 1.78. A. 6,48 gam. B. 8,1 gam. C. 8,8 gam. D. C H 3 - C O O - C H 2 - C O O H . D. Kh6ng xac dinh dugc. Hay chon c6ng thiJc diing. Hay chon dap s6' diing. Este X C O cong thurc phan tir C4H5O2 khi tac dung v6i dung dich 1.80. H6n hgp M g6m 2 este dan chiJc X. Y han kem nhau mot nhom CH2. NaOH, thu dugc 2 san pham c6 kha nang tham gia phan irng trang bac. Cho 6,7 gam h6n hgp M tac dung vCra dii vai 1 0 0 ml dung djch NaOH C6ng thirc ca'u tao ciia X la : I M , thu dirge 7,5 gam h6n hgp hai muoi. A. C H 3 - C O O - C H = CH2. C6ng thiic ca'u tao ciia X va Y la : B. H - O O C - C H 2 - C H = C H 2 . A. C H 3 - C O O - C 2 H 5 va H - C O O - C 2 H 5 . C. C H 2 = C H - C O O - C H 3 . B. C H 3 - C O O - C H = CH2 va H - C O O - C H = CH2. D. H - C O O - C H = C H - C H 3 . C. C H 3 - C O O - C 2 H 5 v a C H 3 - C O O - C 2 H 2 . Hay chon c6ng thiic dung. D. H - C O O - C H 3 va C H 3 - C O O - C H 3 . Hay chgn cong thirc diing. Cho 8 9 gam chat beo (RCOO)3C3H<5 tac dung vira du v6i 1 5 0 ml dung dich NaOH 2 M , thu dugc xa phong va glixerol vdi khd'i lugng tuong 1.81. Cho biet hang so can bang ciia phan ling este hoa : ling la : R - C O O H + R'-OH 1.79. A. 61,5 gam va B. 91,8 gam va C. 85 gam va 18,5 9,2 15 < » R - C O O H - R ' + H2O ; Kc = 4. gam. gam. gam. Ne'u cho h6n hgp ciing so mol axit va ancol tac dung vdi nhau thi khi phan urng este hoa dat tori trang thai can bang c6 bao nhieu % axit va ancol da bi este hoa ? D. Kh6ng xac dinh dugc. A. 50%. Hay chon dap dn diing. B. 66,7 % . Chia 7,8 gam h6n hgp ancol etylic va ancol d6ng dang ROH thanh hai phin bang nhau. C. 75%. PhSn 1 cho tac dung vdri Na (du), thu dirge 1,12 lit H T (dktc). D. Khong C O gid t r i xac dinh. Hay chon dap s6' dung. 1.82. Chiroitg2 Cho 10,4 gam este X ( C 4 H 8 O 3 ) tdc dung vCra du v6i dung dich chiJa 0,1 m o l N a O H t h i thu duoc 8,9 ^"-^ mu6'i. CnCBOHIDRRT C6ng thiic ca'u tao dung cua este la : A. CH3 - COO - CH2 - CH2 - O H . B. H - C O O - C H 2 - C H 2 - C H O . 2.1. C. H O - C H 2 - C O O - C 2 H 3 . D. A . T i n h bSt va xenlulozo k h i chay 6iu cho n^^o^ • " H J O CH3 - CH(OH) - COOCH3. C. T i n h b6t va xenlulozo d6u khong tan trong nu6c. D) Thuy phan tinh bot va xenlulozo den tan cung trong moi truong axit (H2SO4 loang) deu thu duoc glucoza ( C ^ H j ^ O f , ) , Uhg v6i cong thurc phan tir C3H(;02 c6 bao nhieu d6ng phan mach ho CO the tac dung vol Na va bao nhieu d6ng phan mach ho khong tac dung vdfi Na ? A . 2 va 5 ddng phan. =6:5. B. T i n h b6t va xenlulozo d6u c6 the lam thiJc an cho nguori va gia sue. Hay chpn c6ng thiJc dung. 1.83. ^'"^ ^^^^ "^^ • ^^'^^ xenlulozo la nhirng polime thidn nhien c6 c6ng thifc phan tiJ ( C g H i o O ^ ) ^ ? Hay chpn dap an dung. 2.2, B. 3 va 4 d6ng phan. C. 4 va 3 ddng phan. D . 5 va 2 d6ng phan. ' • • .,, , C6ng thiJc t6ng quat ciia hidratcacbon la : A- CnH2nOm; B. ( C H 2 0 ) ^ ; C. D) C„(H20)^; C„(H20)^. Hay chon c6ng thiJc diing. Hay chon dap an diing. 2.3. G l u x i t thu dupe trong qua trinh : A . Quang hop. B. T h i i y phan saccarozo. C. Tuong tac ciia cacbon v6i nude. D. Hoat d6ng s6'ng ciia men. Hay chpn dap 2.4. dung. ,( ' T i n h chat dac trutig c i a glucozo la : 1. Cha't ran ; 2. Co v i ngpt ; 3. It tan trong nudfc ; The hien t i n h chat v6'n c6 : 4. Cua ancol ; 5. Cua axit ; 6. Ciia andehit ; 7. Cua este. NhiJng t i n h cha't nao neu diing ? 26 „ . • ' ' ^' ' 27 2.5. A . 1, 2, 4, 6 ; B. 1, 2, 3, 7 ; Nh&ng tinh chat ndu sai : C. 3, 5, 6, 7 ; D. 1, 2, 5, 6 . A . 2, 5, 6, 7 ; B. 2, 5, 7 ; C. 2, 3, 4, 6 ; D. 3, 5. Glucoza va frutozo la : A . Disaccarit. 2.9. T i n h cha't dac trung ciia xenluloza la : ling este hoa vdri axit ; 7. De dang thu dugc tir dau mo. Hay chon dap an diing. Nhffng tinh cha't neu dung : C6ng thu-c hai dang mach vong ciia phan tir glucoza ( a - glucoza va P - glucoza) khac nhau a ch6 : A. V i . C. V| t r i tuang d6'i ciia nhom h i d r o x y l a nguyen ti!r C, trdn mat phang A . 1, 2, 4, 5, 6 ; B. 1, 3. 5 ; C. 2, 4, 6, 7 ; D. Tat ca. Hay chon dap an dung. B. V i t r i cua nhom andehit trong mach cacbon cua phan tir glucoza. 2.10. .i-'-.S T i n h b6t va xenluloza khac nhau cr ch6 : A . Ve thanh phin phan tilr. ciia vong phan t i i . 2.7. . ca'u true thang ; 5. K h i thiiy phan tao thanh glucoza ; 6. Tham gia phan D. Andehit va axit. , , ,„ y 1. Cha't ran ; 2. Mau trang ; 3. Tan trong cac dung m 6 i hiJu ca ; 4. Co C. A n c o l va xeton. 2.6. , , Hay chon dap an dung. ' ' B. D6ng phan. , D. Kha nang phan ling. B. V6 ca'u true ciia mach phan tir. Hay chon dap an dung. C. D6 tan trong nu6c. T i n h chat dac trimg ciia saccaroza la : D. Dae trung ciia phan iitig thiiy phan. l.Polisaccarit ; 2.Chat tinh the' mau trang ; 3.Khi thuy phan tao thanh Hay chon dap an diing. fructoza va glucoza ; 4.Tham gia phan ling trang bac ; 5.Phan ting v6i d6ng (H) h i d r o x i t . Nhung tinh cha't ntu dung : A . 3, 4, 5 ; B. 2, 3, 5 ; C. 1,3, 4, 5 ; D. 1,4, 5. 2.11. i > • , i'J h'' " ' t <> " '-si ' G l i x e r o l tristearat Ik : A . M 5 d6ng vat. B. Chat ran. C. Chat tan t6t trong nude. Hay chon dap an dung. D. San phim hidro h6a g l i x e r o l tripanmitat. 2.8. T i n h chat dac trirng cua tinh b6t la : I . Polisaccarit Hay chon dap an diing. ; 2. Khong tan trong nude ; 3. V i ngpt. Thijy phan tao thanh : 4. Glucoza ; 5. Fructoza ; 6. L a m xanh iot ; 7. 2.12. Co 4 hop cha't hOu ca : A x i t axetie, g l i x e r o l , ancol etylic va glucoza. De phan biet dugc 4 cha't nay chi cin dang mOt cha't lam thu6'c thir la : La nguyen litu di6u ch6'dextrin. A . Quy t i m . 28 Mm, OQ C. P h a n t u k h 6 ' i c i i a x e n l u l o z o b a n g c u a t i n h b 6 t . B. CaCOg. D . K h 6 n g x a c d i n h dugfc. C. C u O . D. Cu(0H)2 trong m o i trudng kiem. Hay chpn dap an diing. • ' 2 17. H a y c h o n dap a n d u n g . 2.13. (-C6H,o03-)n D e phan biet dung djch g l u c o z o va ancol etylic c 6 the dung : Hitu A. Natri k i m loai. sua't c u a q u a t r i n h s a n xua't l a 7 5 % . T i r 1 ta'n t i n h b 6 t c 6 l l n 2 0 % B. 8 0 0 k g C2H5OH . C. 1 0 0 0 k g C 2 H 5 O H . H a y c h p n dap a n d i i n g . D. 620,5 k g C2H5OH. C o cac l o a i d i r d n g a n sau, ducfng n a o t h a m g i a p h a n l i n g t r a n g g i r o n g ? 2.18. A . Saccarozor. T i n h k h 6 ' i l i r p n g g l u c o z o c ^ n t h i e t d ^ \tn m e n t h a n h a n c o l e t y l i c v 6 i hieu B. F r u c t o z o ; sua't 9 0 % . Biet rang qua trinh l e n m e n t h u dupe 11,2 l i t CO2 ( d k t c ) . D a p s6' l a : C. G l u c o z o . A. 45 g a m glucozo. D. Ca A , B, C d^u dung. 2.15. > C2H5OH A . 3 4 0 , 7 4 k g C2H5OH . NH3. D . C h i d i j n g d u n g d i c h bac n i t r a t . 2.14. > CgHijOg tap c h a t san xua't d u p e b a o n h i e u C 2 H - , 0 H ? B. D u n g d i c h a m o n i a c . C. D u n g d i c h bac n i t r a t t r o n g So d d s a n xua't a n c o l e t y l i c tCr t i n h bOt : B. 4,5 g a m glucozo. K h i d u n n o n g d u n g d i c h d u 6 n g s a c c a r o z o c 6 m a t a x i t H2SO4 loang, C. 5 0 g a m g l u c o z o . thu duoc dung dich m d i : D. 5 g a m glucozo . A. Chi C O dii5ng glucozo. H a y c h p n d a p s6' d i i n g . B. C h i i a c a duofng g l u c o z o , c a ducrng fructozo. C. D u n g d i c h t h a m g i a p h a n urng t r a n g g u a n g . 2.16. 2.19. C6 4 I p d i r n g 4 d u n g d i c h k h 6 n g m a u b| m a t n h a n l a : d u n g dich glucozo, d u n g djch g l i x e r o l , dung d j c h ancol etylic va dung d i c h axit D. Ca B va C d^u dung. a x e t i c l o a n g . Thu6'c t h i r c 6 t h e d i i n g de p h a n b i e t 4 d u n g d i c h t r e n l a : H a y c h o n dap a n d u n g . A . C u ( 0 H ) 2 t r o n g m 6 i t r u 6 n g k\6m ( C u ( 0 H ) 2 / 0 H " ) . X e n l u l o z o va t i n h b 6 t l a n h i r n g p o l i s a c c a r i t c 6 p h a n tir khd'i ra't I d n . K h i B. D u n g d i c h A g N O j / N H j . so s a n h n g u d i t a tha'y : A . P h a n tir kh6'i c u a x e n l u l o z o n h o h o n c i i a t i n h b 6 t . B. P h a n t i r kh6'i c i i a x e n l u l o z o idn h o n cua t i n h b 6 t . C. D u n g d i c h b r o m . D. Natri k i m loai. H a y c h p n dap an d i i n g . 2.20. De phan biet dung dich cac chat rieng bidt g6m : tinh b6t, glucozcr va saccaroza ngirdi ta diing thu6'c thir: A. Dung dich iot. , , B. Dung dich HCl. C. Cu(OH)2/OH~. 4) Glucoza tac dung v6i luang du anhidrit axetic (CH3CO)20 thu duac este chu-a 5 goc C H 3 C O O - , chtJng to trong phan tix glucoza c6 5 nhom - O H ; 5) Khi d6't chay hoan toan glucoza thu dugc s6' mol CO2 bang s6' mol H2O; 6) Cu- 1 mol glucoza tham gia phan iJng tr^ng guang cho 4 mol Ag. Nhirng phat bi^u nao diing ? A. 1,2, 3, 4 ; B. 2, 3, 4, 5; C. 1,2, 4, 5 ; D. 2. 4, 5, 6. D. Dung dich AgNOj/NH,. Hay chon dap an diing. 2.21. Thiiy phan m gam tinh bot, san pham thu dirge dem 16n men d^ san xuat ancol etylic. Toan bo khi COT sinh ra cho qua dung djch Ca(0H)2 dir, thu du'oc 750 gam ket tiia. Neu hieu sua't m6i qua trinh la 80% thi m CO gia trj la : A. 949,2 gam ; B. 945,0 gam ; C. 950,5 gam; D. 1000,0 gam. Hay chon dap s6' dung. 2.22. Trong m6t nha may ancol, ngucfi ta dung nguyen lieu la mun cua chiJa 50% xenluloza d^ san xua't ancol etylic. Biet hieu sua't ciia ca qua trinh la 70%. Di san xua't 1 ta'n ancol etylic thi kh6'i lugng miin cua cAn dCing la : A. 500 kg ; B. 5051 kg ; C. 6000 k g ; D. 5031 kg. Hay chon dap an diing. 2.23. Khi hoc bai gluxit, mdt hoc sinh da tdng ke't : 1) Tat ca cac hop chat c6 cong thiic thuc nghidm (c6ng thlic dan gian nha't) la CH2O dfiu la gluxit ; 2) Khi khi!r hoan toan glucoza (C6H]206) thanh n-hexan, chiimg to glucozo CO mach cacbon kh6ng phan nhanh gdm 6 nguyen tir cacbon ; 3) Glucoza vCra c6 tinh khCr, vura c6 tinh oxi h6a ; 32 2.24. Co cac dung dich khong mau : HCOOH, CH3COOH, glucozo (C6H,206), glixerol, C2H5OH, CH3CHO. Diing nhirng cap chat nao de nhan biet ca 6 chat ? A. Cu(0H)2 , quy tim, AgN03 trong dung dich NH3. B. Quy tim, NaOH va Ag20 trong dung dich NH3. C. Cu(0H)2 , AgjO trong dung dich NH3 va NaOH. D. Quy tim, Ag20 trong dung dich NH3, H2SO4 dac. 2.25. Phan urng nao chirng to glucoza c6 the t6n tai du6i dang mach vong ? A. Oxi hoa glucoza bang Cu(0H)2 trong m6i truomg kiim. B. Oxi h6a glucoza bang dung dich AgN03 trong dung dich NH3. C. Cho glucoza tac dung v6i CH,OH khi c6 mat hidro clorua khan (HCl) de thu dugc metyl glucozit. D. Khir glucoza bang H2 Ni xiic tic,) 2.26. Phan irng n^o khfing th^ tao ra glucoza 1 A. H - C H O dung dich Ca(OHb ^ B. CO2 + H2O '^^"^attrcri.diepluc ^ C. Thijy phan mantoza . D. Trung hgp 3 phan tir CH3CHO . 33 2.27. De phan bidt 2 dung dich KI va KCl bang h6 tinh b6t, ngucfi ta diing them mot so chat sau day. A. O3 (ozon). B. FeClj . C. CI2 hoac Brj. D. Khong cin diing chat nao. Hay chon dap an sai. C^HijOg ^ r.H^OH ^ C10H13O5 ; C. CioH,407 ; Hay chon c6ng thiic diing. ^ B. C12H14O7 ; D. C,2H,405 ; \ 2.32. Cho 36 gam glucoza tac dung hoan toan v6i dung dich AgN03 trong NH3 thi thu dugfc bao nhieu gam bac kim loai ? A. 43,2 gam ; B. 21,6 gam; C. 10,8 gam ; D. 5,4 gam. 2.29. Co 4 goi b6t trSng CaCOg, NaCl, SiOj, xenluloza. Ngu5i ta phai phan bifit 4 chat do bang cac thu6'c thi!r A. Dung dich H2SO4 dac. | B. Dung dich HCl va AgNjOj 2.33. Cho 4,5 kg glucoza len men. Hoi thu dugc bao nhieu lill ancol ei'lic nguyen chat (d = 0,8 g . m f ' ) va bao nhieu lit CO2 (dktci? Biet hiOu sua't phan u:ng la 80%. A. 2,3 lit ancol va 560 lit CO2. B. 2,3 lit ancol ya 636 lit COj. C. 2,3 lit ancol va 725 lit COj. D. 2,3 lit ancol va 896 lit CO2; Hay chon dap an diing. 'C. Dung dich HCl va O2 (d6't chay). D. Dung dich HCl va dung djch NaOH. Hay chon dap an diing. ) 2.30. TCr tinh bSt hoac xenlulcyza c6 th^ di^u ch^ cao su buna theo sa 66 sau: (CgHjoOs^ X ^1 Y Z ^ Cao su Buna. Hay chon chat X, Y, Zj thich hgp. CH2 = C H 2 CH3-CH2-CI Hay chon sa 66 dung. 2 31. Xenluloza diaxetat (chat X) duac diing d^ san xua't de phim anh hoac ta axetat. Cong thirc thirc nghiem (CTDGN) ciia X la : A. 2.28. Tinh bot va xenluloza ichac nhau 0 tinh cha't : A. Tinh tan trong nirdc. B. Phan u"ng thiiy phan ra glucozo. C. Phan irng v6i dung dich I2. D. Phan ling chay. Hay chon dap an dung. A. ^ CgHijOg ^ C2H5OH B. ^ CgHijOg ^ C2k50H C. ^ C6H,206 CjJisOH D. ^ CH2=CH-CH = CH2 CH3-CH2-CH2-CH3 ^ ^ " 2.34. Tir 100 kg gao chira 81% tinh b6t c6 the di^u che' dirge bao nhieu l\ ancol etylic nguyen chat ( d = 0,8 g.ml"') va tCr ancol nguyen cha't do san xua't duac bao nhieu lit ancol 46° ? Bie't hieu sua't dieu che la 75%. A. 50,12 lit va 100 lit. B. 43,125 lit va 93,75 lit. C. 43,125 lit va 100 lit. D. 41,421 lit va 93,76 lit; Hay chon dap an dung. mi •MS .A 35 2.35. Cho so 66 bidn h6a : Y., Nhu vay X phai la : +Cu(OH)2 -> T,kei liia do g a d ; C. Chiing d^u tham gia phan irng este h6a v6i HNO3, CH3 -COOH. D. Chiing d6u kh6ng tan trong nudrc. Hay chon dap an sai. A. Glucoza; B. Fructozo ; C6 4 gdi bot trang : glucoza, saccarozo, tinh b6t, xenluloza. Hay chon 2.40. b6 thu6'c thir d^ c6 the phan biet duoc ca 4 cha't: C. Xenlulozo ; D. Sacarozo. A. Nu6c., dung djch AgN03 trong NH3. * Hay chon dap an dung. B. Nudrc, O2 d6't chay, dung dich AgN03 trong NH3. 2.36. Cho 360 gam glucozo len men th^nh ancol etylic (gia six chi xay ra phan umg tao thanh ancol etylic) va cho ta't ca khi cacbonic thoat ra hap C. Nude, dung dich AgN03 trong NH3, dung dich I2. thu vao dung dich NaOH du thi thu dugc 318 gam Na2C03. Tinh hieu D. Nude,.dung dich HCl, dung dich AgN03 trong NH3. sua'l phan ling len men. Hay chon dap an dung. A. 50% ; B. 62,5% ; Dung dich NaOH C. 75^0 ; Hay c/hon dap An diing. ' ^ d u n g dich xanh lam D. 80% . 2.41. So sdnh tinh cha't cua glucoza, saccaroza, fructozo, xenluloza : 1) Ca 4 cha't d^u de tan trong nu6c do deu c6 nhom -OH . 2) Triif xenluloza, 3 cha't con lai d6u c6 th^ tham gia phan ii'ng trang 2.37. Cho/360 gam glucozo len men thanh ancol etvlic (gia sir chi xay ra guong. pha/n iJng tao thanh ancol etylic). Hoi thu dugrc bao nhidu ml ancol etpic nguyen chat (d=0,8 g.mf') ? Bie't hieu su&t phan iJng la 65%. 3) Ca 4 chat diu c6 ihi tac dung v6i Na vi d^u c6 nhdm - O H . 132.4 m l ; B. 149,5 tnl ; 4) Khi d6't chay hoan toan 4 cha't tren d6u thu dugc s6' mol CO2 va hai nu6c bang nhau. , y. 250 m l ; D. 214,8 iml. Cac so sanh sai la : 2.38. / So sanh glucoza va xenluloza ta tha'y : A. 1, 2, 3 ; B. 1, 2, 4 ; A. Chiing d6u tham gia phan iJng trang bac. C. 2, 3, 4 ; D. 1, 2, 3, 4 ; B. Chung deu dl tan trong nu6c. C. Chung d6u duac tao thkuh nhcf phan irng quang hap. D. Chung d6\i la cac polime tir nhifen. Hay chon ddp an dung. !.39. So sanh tinh b6t va xenluloza ta tha'y : A. Chiing ddu dirac tao thanh nhd phan irng quang hap. ; B. Chiing dfeu thiiy phan (xiic tac H"^) tao ra glucoza. \ >6 2.42. Cho axit nitric dac (c6 mat H2SO4 dac) t^c dung \6i cdc cha't sau: glixerol, xenluloza, phenol, toluen thu dugc c^c san pham c6 c6ng thiJc tuong irng la : C3H5N3O9 (1), (C6H7N30,,)n (2), C6H3N3O7 (3), C7H5N3O5 (4). Nhung cha't thugc loai hop cha't nitro la : A. 2, 3 ; B. 2, 4 ; C. 2, 4, 5 ; D. 3, 4. Hay chon ddp dn diing. 2.43. Mot loai xenlulozo c6 kh6'i lirgng phan tir 1.500.000 u (dvC). Hoi thuy phan hoan toan 1 mol xenlulozo thu dugc bao nhieu mol glucozo ? A. 8627 ; B. 9259 ; C. 12.048 ; D. 12.815. 2.44. Cho axit nitric dac (c6 mat H2SO4 dac) tdc dung v6i xenlulozo thu dugc njiieu este khac nhau, trong do c6 este X cMa 11,1%N, bie't khoi lugng phan tir ciia nhom mat xich CgHjoOs la 162. C6ng thiic ciia este Xla: Chvtcfng 3 nMrN - 3-1. n/viiNO nxiT - PROTCIN Khi hoc bai amin, mgt hgc sinh da tdng kd't : 1) Amin la hgp chat dugc tao thanh do nhom -NH2 lien ket vdi gg'c hidrocabon R-. 2) Amin la hgp chat dugc tao thanh do thay the mot hay nhidu nguyen tir hidro cua phan tir NH3 bang m6t hay nhieu goc hidrocacbon. A. (C6H702(OH)2(ON02))n. 3) Tat ca cac amin ddu tan tot trong nude do tao thanh lien ket hidro voi nude. B. (C6H702(OH)(ON02)2)n- C. (C6Hv02(ON02)3)n • 4) Tiiy theo so nguyen tir H trong phan tir NH3 dugc thay the boi goc hidrocacbon ta c6 amin bac 1, bac 2, bac 3. D. H6n hgp d6ng so mol A va B. 5) Tat ca cac amin dfeu tac dung vdri axit de tao thanh mu6'i. Nhung phat bieu dung la : Hay chgn cdng thirc dung. 3.2. A. 1,2, 5 ; B. 1,2, 4, 5; C. 2, 4, 5 ; D. 1,3, 4. Hay chgn dap an dung. Co cac c h a t : N H 3 (1), (CH3)2NH (2), CgHj - NH2 (3), CH3 - NH2 (4), CH3-C6Hs-NH2(5). Tinh bazo cua cac chat dugc x6'p tang din theo day : • A. 1 < 2 < 3 < 4 < 5. ^ B. 3 < 5 < 1 < 4 < 2 . C. 5 < 3 < 4 < 2 < 1. D. 3 < 5 < 4 < 2 < 1 ; Hay chgn day sap xep dung. 3-3. Co dung djch cac chat : NH3 , ( C H 3 ) 2 N H , S6 cap chat tac dung dugc v6i nhau la : HCl , C6H5NH3CI, FeCls . > l-l -1 i n 39