Tài liệu Cẩm nang ôn luyện thi đại học 18 chuyên đề hóa học 7

Cty TIMHH MTV DVVH Khang Vigt Ca'm nang 6n luygn thi dgi hgc 18 chuygn dg H6a hgc - Nguygn Van htai ''^''[ mstm^ ' • V ^ y : m = 127.0,1 + 74,5.0,2 = 27,60 gam. - > Dap an B. ' ' ' ' ' r 5 = - ^ i man ^ Lin< 1/: Trong bai nay cac em de quen KCl khi h'nh khoi lugng muol va chor, nham phuong an D! ^ xet: Vi d\ 6: Cho 0,02 mol amino axit X tac dung vira dii voi 10ml dung dich HC| A. H2NC2H3(COOH)2. C. (H2N)2C3H5COOH. • D. H2NC4H8COOH. 'f^^'Ky: ^ Laigidi: gam X can 60ml dung djch HCl I M . Cho 7,66 gam X tac dung vira du vol dung dich KOH, thu dugc dung dich Y. Co can Y thu dugc m gam muoi "^"^ khan. Gia tri cua m la A. 11,31. B. 11,46. - Ta c6: nHci: nx = 1:1 — Trong X c6 chiia 1 nhom - N H 2 > " N a O H : nx = 2:1 H2N-R-COOH Trong X chua 1 nhom - C O O H + HCl 0,02 • "KOH '-i' R = 56 (C4H8) = 153,5 Dap an D. A. H2N-C3H6-COOH. Laigidi: Nhan xet: nna: nx = 1:1 nNaOH : nx ' •;„;••.••,:..•• 10.0,06 , ^ n o ( X ) = — ^ = 0 , 2 mol. ;f ^ R + 142,5 = ' J AMti'Dr ncooH V. f ' , . ^ = 0/1 mol. , 1 , » B. Valin. C. Lysin. D. Alanin. 1 '• Lai gidi: |j xay ra hoan toan, somol NaOH da phan ling la D. 0,55. iiCJg -i^n' Phuong an C: Lysin c6 cong thuc cau tao (NH2)2C5H9COOH. W^J^-tHD dung dich CO moi truong b a z a l a m quy tim chuyen xanh. HCl 2M, thu dugc dung djch X. Cho NaOH du vao X. Sau khi cac phan ung C.0,65. * Trong phan tir lysin c6 2 nhom chuc amin va 1 nhom chuc axit cacboxyl -> = 183,5 -> R = 41 (C3H5) ^ Dap an C. B.0,50. ^ , lam doi mau qui tim. V i du 8: Cho 0,15 mol H2NC3H5(COOH)2 (axit glutamic) vao 175ml dung dich A. 0,70. 3 :y . r / Loai A, B, D vi dung dich cac chat nay c6 moi truong trung tinh va khong > ClH3NR(COOH)2 0,1 ' ' 10: Dung dich nao sau day lam chuyen mau qui tim thanh xanh A. Glyxin. = 2:1 -> X chua 2 nhom - C O O H . - ,?* iv- 0,1 10 ! -> Dap an B. — X chua 1 nhom -NH2. > Ggi cong thuc cua X la H2N-R(COOH)2 Mol: Matkhac: no(x)=2ncooH ^ H mol H2NR(COOH)2 + H C l 80/16 Tang giam khoi lugng: m = mx + 0,1(39-1) = 7,66 + 0,1.38 = 11,46 gam., H D.(H2N)2C3H5-COOH. mol; nwaOH = 0,02 no . Nhqn thay: Khi tac dung voi KOH, - C O O H se chuyen thanh - C O O K nen: B. H2N-C2H3(COOH)2. C.H2N-C3H5(COOH)2. n H c i = 0,01 80 I Cac em can luu y: n N = n N H 2 = n H c l - > n N ( x ) = 0,06 mol. vai 100ml dung dich NaOH 2M. Cong thuc cau tgo cua X la: '•••••"•r "^o I De thay: nf,jH9 = " H C l = 0/06 mol. I M , thu dugc 18,35 gam muoi khan. Mat khac, 0,1 mol X tac dung vira dii ^ T - . ' i - i u - i T u ti 1? khoi luong:—— = — -» = = —. • ^ mN 21 nN 21/14 3 ^a02 Vi dv 7: Cho X la mot amino axit. Cho 0,1 mol X tac dung vira du 100 ml HCl I =0/1 mol- xiw^ 3 07 -> ClHaN-R-COOH = D. 9,12. N/iflM Aret: > ClHaN-R-COOH ' + C.9,85. Laigidi: G i--' -'i^w,; - dung dich chua 0,02 mol NaOH. Cong thuc cua X la r-;.!--iv::K:;<>:;>^^(,; i Tong so'mol cac axit c6 trong X = ncooH + nHci = 0,15.2 + 0,35 = 0,65 mol 2M thu du-oc 3,07 gam muoi khan. Mat khac 0,02 mol X tac dving vua du v6i , -> Dap an C. ||l^i d\ 11: Eote X dugc dieu che tir a-aminoaxit (chua 1 nhom - N H 2 va mot nhom - C O O H ) va ancol etylic. Dot chay hoan toan 1,03 gam cha't X thu dugc 1,76 gam CO2; 0,81 gam H2O va 112ml N2 (dktc). Cong thuc cau tao cua X la: CSiii naiig on luy^n thi d^ii hyc 18 chiiyen d6 116;; ligc - Nguyen V'Sii Hdi Cty TNHH MTV DVVH Khang VIgt A. H2N-CH2-COOC2H5. B. C. C2H5-CH(NH2)-COOC2H5. D. C2H3CH(NH2)COOC2Hs. CH3-CH(NH2)-COOC2H5. nco2 = 0/04 m o l ; n n j o = 0,045 m o l ; n ^ ^ = 0,005 m o l . X : y : 1 = nc : H H : ^ dang ke'tiep) thu dupe CO2 va H2O voi ti 1 so'mol nco2- " H a O ^ l • 2 • Hai ^ a m i n la , ,, ... . A. CH3NH2 va C2H5NH2. • ' A '{fxd f«o/: : = 0,04 : 0,09 : 0,01 = 4 : 9 : 1 --.^MM: Nhan xet: A. M e t y l a m i n v a e t y l a m i n ,1':!. Tie h o n h o p 2 a m i n o axit la A l a v a Gly, c6 the tao ra to'i da 4 d i p e p t i t la: A l a - A l a ; Gly-Gly; A l a - G l y va G l y - A l a . , = „ —>• D a p an D . A. Tac d u n g v o i d u n g d i c h FeCb B. Tac d u n g v o i d u n g d i c h Br2 ^ i^P C. Tac d y n g v o i d u n g d i c h H C l D . Do'i m a u q u y t i m . Bai 8: D a y g o m cac cha't deu l a m gia'y q u y t i m a m c h u y e n sang m a u xanh la: A . A n i l i n , m e t y l a m i n , amoniac. - B. A m o n i clorua, m e t y l a m i n , n a t r i h i d r o x i t . C. A n i l i n , amoniac, n a t r i h i d r o x i t . C.0,3. Bai 2: T r u n g hoa h o a n toan 8,88 g a m m p t a m i n (b^c m p t , m a c h cacbon khong • B. CH3CH2CH2NH2. D. H2NCH2CH2CH2NH7.. B. N u o c b r o m . i m g d u p e v o i n u o c b r o m la B. 8. . ,, D. C H 2 = C H - N H - C H 3 . A. 3. Benzen dving v o l d u n g d j c h H C l t h u dupe 14,2 g a m h 6 n h p p m u o i Cho h o n h(?P D . C4H11N va C5H13N. B. 1. D.4. C.2. -"No,a(H,so,d) ^ ^jtrobenzen ^^^""""^ > a n i l i n . doan tao t h a n h a n i l i n dat 50%. K h o i l u p n g a n i l i n t h u d u p e k h i d i e u che tir i j t h i i c p h a n t u cua cac chat t r o n g hSn h p p la: ' D. 5., C. 7. Bie't h i | u suat giai doan tao t h a n h nitrobenzen d a t 60% v a h i ^ u suat giai fc m u o i d o vao d u n g d i c h A g N 0 3 d u t h u dupe 28,7 g a m ke't tua. V a y cong C. C3H9N v a O H n N . * ' Bai 12: N g u d i ta d i e u che a n i l i n bang so d o sau: Bai 4: Cho h o n h p p X g o m 2 a m i n d o n chuc la d o n g dang ke tiep n h a u tac B. C2H7N va C3H9N. 300m *,„,.KH, t h u d u p e t o i da bao n h i e u d i p e p t i t khac n h a u B. C H 2 = C H - C H 2 - N H 2 . CM A. C H s N va C2H7N. CH2=CH-COOH, Bai 11: N e u t h i i y p h a n k h o n g hoan toan pentapeptit G l y - A l a - G l y - V a l - G l y t h i h o i deu d o 6 c u n g d i e u ki?n). A m i n X tac d y n g v o i axit n i t r o 6 nhi?t &Q c. C H 3 - < : H 2 - N H - C H 3 . C2H2, C2H4, C2H5OH, C6H5NH2 (anilin), CeHsOH (phenol), CsHe (benzen). So chat t r o n g day p h a n ra 8V l i t h o n h p p g o m k h i cacbonic, k h i n i t o v a h o i n u o c (cac the tich k h i va A. C H 3 - C H 2 - C H 2 - N H 2 . y. D . Gia'y q u i t i m a m . Bai 10: C h o d a y cac chat: CH4, Bai 3: D o t chay h o a n toan V l i t h o i m o t a m i n X bang m p t l u p n g o x i v u a d u , tao t h u o n g , giai p h o n g k h i n i t o . Chat X la , A. D u n g d i c h phenolphtalein. C. D u n g d i c h N a O H . p h a n n h a n h ) b a n g axit H C l , tao ra 17,64 g a m m u o i . A m i n c6 cong t h i i c la C. H2NCH2CH2NH2. .)»-;rt1 T h u o c t h u de p h a n biet 3 chat l o n g tren la D.0,2. A. H2NCH2CH2CH2CH2NH2. fs^iff Bai 9: Co 3 chat l o n g a n i l i n , benzen, stiren, d u n g rieng b i ^ t t r o n g 3 Ip m a t nhan. Cho 6,0 g a m X tac d y n g v o i d u n g d i c h H C l (du), so'mol H C I p h a n u n g la B.0,4. ' Ofin D. M e t y l a m i n , amoniac, n a t r i axetat. n g u y e n t i i C ) bang o x i vira d u , t h u dirge 0,7 m o l h o n h o p Y g o m k h i va hoi. A . 0,1. ci,,) ^ Bai 1: D o t chay hoan toan 0,1 m o l m o t a m i n X (no, mach ha, p h a n ttr chiia > 2 , D. Etylamin va butylamin Bai 7: A n i l i n eo t i n h cha't hoa hpc co ban nao g i o n g v o i m e t y l a m i n ? Luu y: D i p e p t i t A l a - G l y khac d i p e p t i t G l y - A l a . 3. BAI TAP O N L U Y E N '' " ' B. E t y l a m i n va propylamirv C. P r o p y l a m i n v a b u t y l a m i n s! nt.E)^:4iTJ fiJO. : .akri .a ' . • Laigidi: D. C2H5NH2 va C4H9NH2. H2SO4 CO p H bang 2. H a i amin t r o n g X la: la C.2. C2H5NH2vaC3H7NK2. dong dang). T r u n g hoa 0,42 gam X can dung 1 l i t dung dich gom H C l va Vi d\ 12: So' d i p e p t i t to'i da c6 the tao ra tir m p t h o n hp-p g o m alanin va glyxin B. 1. "•" . Bai 6: H o n h p p X gom hai amin (no, don chiic bac I , ke' tiep nhau t r o n g day C o n g t h i i c p h a n tit cua X la C4H9O2N —> D a p an A A. 3. B C. C3H7NH2 va C4H9NH2. in G p i cong t h i i c cua X la C x H y 0 2 N . 1 ^ a i 5: Dot chay hoan toan hon hgp hai amin (no, don chuc, mach ho, dong «7 156 g a m benzen la . A . 186,0 g a m . B. 55,8 gam. C. 93,0 gam. D . 111,6 gam. CJm nang 6n luy$n thi dgi hpc 18 chiiy§n di H6a hpc - Nguygn Van H5i I HI/6NG DAN-L61 GIAI Bai 13: Thuoc thu dugc dung de phan biet Gly-Ala-Gly vai G l y - A l a la . A . D u n g dich N a O H . C . Cu(OH)2 trong moi truong kiem. Ggi cong thiic ciia X la CnH2n+2-x(NH2)x B. Dung dich N a C l . D. Dung dich H C l . CnH2n.2«N. . Bai 14: C o bao nhieu tripeptit (mach ho) khac loai ma khi thuy phan hoan tohn deu thu duQC 3 aminoaxit: Glyxin, alanin va phenylalanin A. 6. B.9. C . 4. D . 3 . ' r' Mol: ^ D. CH3-COONH-CH2-CH3 Bai 16: D u n nong 51,72 gam hon hgp gom 2a mol tripeptit mach h a X va a mol tetrapeptit mach ho Y voi 300ml dung djch N a O H 2 M (vua du). Sau khi cac Mol: C . 78,96. Mol: 0,12 '''' ' - C . Muo'i phenylamoni clorua khong tan trong nuac. ^ V: •„: C.46,0. D . 22,24. D . 46,9. ' ' ±Af , ,,;:;tiv:-fii|:J.|>:-d£^.i''::S' //-•-^Or-i-^/^V''^'^ ^ . v^ .y^ 7 -^ ^' ,A .nfi q&G '•• , A m i n chiia 1 nguyen tu N . a,, f , i u a . i i - _ . ; v i . . . XCO2 + I H 2 O 2 1 -x^ X la amin bac I Dap 5, A + • •, >> A i^o i iN^^^^^^^Sm:'J 2 0,5y O^ftiij^iwurf! 0,5 .•^.\^y^;^,uh j j^;,, ; nv^iam:mM^!!imfix fnism i v j ,t% Loai B. „ jy^, , ,,«vMH.XB 3rt»B:ff lira-Q:J s'srtob imaM. fv.fi 'ai4: ~ Nhqn xet: V i 2 amin la dong dSng ke tiep RNH2 B.45,1. ]' t^^ 1 x + 0,5y + 0,5 = 8 - > 2 x + y = 1 5 - ^ x = 3 ; y = 9 - > C3H9N. Bai 19: D u n nong 26,9 gam hon hgp gom a mol dipeptit mach h a X va 2a mol A. 41,5. ^' Loai C va D. , /vuv.;.... ;'.'>frji«fe(ff Mat khac. X tac dung voi axit nitro 0 nhiet do thugng, giai phong khi nito Gia tri ciia m la Gia tri cua m la R = 42 (-C3H6-). 4_ amino axit deu c6 mot nhom - C O O H va mgt nhom - N H 2 trong phan tii. amino axit deu c6 mgt nhom - C O O H va mgt nhom - N H 2 trong phan tit. riir^-^ ,S ^ -f- 0,24 CHyN M x + ^)02 ^ phan ung ket thiic, c6 can dung dich thu dugc 41,04 gam muoi khan cua cac phan ling ket thiic, c6 can dung dich thu dugc m gam muoi khan ciia cac ,, ^ « J > R(NH3C1)2 Ggi cong thiic ciia X la CxHyN tripeptit mach h a Y voi 300ml dung dich K O H I M (vua du). Sau khi cac tripeptit mach ho Y voi 400ml dung dich H C l I M (vua dii). Sau khi cac -oo f'i _ Nhqn xet: D u a theo cac dap an Bai 18: D u n nong m gam hon hgp gom a mol tetrapeptit mach ho X va 2a mol C . 25,86. ' f'^'''',^ ,, n 2HC1 Mnmin = 74 ^ Bai 3: khai. B. 27,15. .f; 14 ,,„„;., H • - > Dap an D. D. O dieu ki^n thuong, metylamin va dimetylamin la nhiing chat khi c6 miii A. 33,00. , Bao toan khoi lugng: mnci = 8,76 gam - > nuci = 0,24 m o l sHVi j . . „ r, B. H 2 N - C H 2 - C H 2 - C C ) - N H - C H 2 - C O O H la mgl dipeptit. ^ , R(NH.,2. Bai 17: Phat bieu nao sau day la diing? ' n = X = 2. Gia sii amiII 2 chiic (vi c6 3 trong 4 phuong an). D . 77,52. A . Tat ca cac peptit deu C O phan ung mau blure. o,05x Nhqn xct: D u a theo cac dap an, amin la no, d a n chiic hoac no, hai chiic. , . ^ ' " +^ :f-\hiJ^. > C2H4(NH3C1)2 0,2 Bill: amino axit deu c6 mot nhom - C O O H va mot nhom - N H 2 trong phan tir. B. 72,48. + 2HC1 2 0,1. 2n + x = 6 ^ '-n- ' 0,1 ^ N2 Dap an D. phan ling ket thiic, c6 can dung dich thu dugc m gam muoi khan ciia cac A. 75,72. 0,ln C2H4(NH2)2 B. N H 2 - C H 2 - COOCH2-CH3 C . CHa - N H - C O O - C H 2 - C H 3 0,1 - > X la: C2H4(NH2)2. (o cimg dieu kien nhiet do, ap suat). Cong thiic cau tao ciia X la H2O . 2 -> 0 , l n + 0,1. ^"^^^^^ + 0,05x = 0,7 hoan toan 2,06 gam X thu dugc the tich bang the tich ciia 0,56 gam khi nito A. N H 2 - C H 2 - C H 2 - COC)-CH2-CH3 ^ ^ 1 ^ uCO^ . 4 i j i ; Bai 15: Este X dugc dieu che tii aminoaxit A don chiic va ancol etylic. Hoa hoi G i a tri cua m la ^^^^^O. Mol: 0,2. • > + HCl , <. ^ ft;;- • _ cong thuc chung R N H , . RNH3CI 0,2 .4.7tmyum ' 365 RNHgCl + AgNOs Mol: 0,2 > RNH3(N03) <- + AgCl© J. -> RNH3CI ^ R +50,5 = 71 -» R = 2 0 , 5 . , - Bai5: . •jjj;.:^ , 'v • •• j ^ . / , , ' . ' vui-h, . > C5H2Br3NH24-trang + 3HBr Dap an B. • Taco: f-,... . - = "H2O > —=— =2 2 , .' , fr' -> Hai amin la CH3NH2 va C2H5NH2 • . '., > C2H2Br2 - ' Oir > CH2Br-CHBr-COOH > C6H2Br3NH2i tr.4ng > C6H2Br30Hi tring + "''r in.v,,' ^''X /rtoW + 3HBr ''''' 3HBr ....... ...MH ,^no; Baill: — Dap £.n A. > Khi thiiy phan khong hoan toan pentapeptit Gly-Ala-Gly-Va'-Gly, c6 the Bai6: thu diroc cac loai dipeptit la: Gly-Ala, Ala-Gly, Gly-Val, Val-Gly. pH = 2 -> [H^] = 0,01M -> n = 0,01.1 = 0,01 mol 0,01 <- — Dap an D. > Lim y: Gly-Ala khac Ala-Gly, amino axit viet truoc la amino axit dau amin, G Q I cong thuc chung cua 2 amin la R - NH2 R - N H 2 + HCl > R-NH3CI Mol: , ..^ , CaHsOH (phenol) + 3Br2 - > D a p a n D . -['-f- ' IS , ' • > > C2H2Br4 (anilin) + 3Br2 C6H5NH2 n = 1,5 ' -v. C2H4 + Br2 *' 2n ^; i BailO: CH2=CH-COOH + Br2 _ r, >i'. i.0.t} ' 1 ...-fH!)-.) +) - C2H2 + 2Br2 1 i p * ,, Gpi cong thuc chung cua 2 amin la C - Hj-^g N • Benzen khong tac dung voi nuoc brom. -> Hai goc hidrocacbon ke tiep nhau la: CHs- va C2H5-. DapanA. : i C6H5CH=CH2 + Br2 > C6HsCHBr-CH2Br Anilin tac dyng voi nuoc brom tac thanh ket tiia trang: C6H5NH2 + 3Br2 0,2 ,.!!«f!into1< aOl < con viet sau la dau cacboxyl. ""'-^'^ R - N H 2 =42 -> R =26 -> CH3-vaC2H5-> Dap an A. QH6 / v» , * Mol: ^"NO,d(H,SO,d) 2 naniiin = 2. ' Loai B vi chi c6 anilin tac dung voi nuoc brom. - > Phuong an C: Anilin va metyl amin deu c6 tinh baza nen deu tac dyng voi dung dich HCl. -> maniiin Dap . 50 100 100 = 0,6 , (i +£\:»iS *2"''''-''*-"'''~'' ' ''^ , • • --^Jnc q^^O ' , mol = 0,6.93 = 55,8 gam. : !:3 iom ' ^ ' oky iv A • ^'q 6:>:i,^;iOf, • .. ifi;'!- ' ' .Is-jno:;; - • Nhqnxet: ->DapanC ; ^ fW an B. Bail3: Loai D vi chi metylamin lam doi mau qui tim. ^'-^"^'""^ > C6H5NH2. C0H.NO2 2 ^ 60 Loai A vi chi c6 metylamin tac dung voi dung dich FeCIa. ^ -n i v • " • Gly-Ala-Gly la tripepit nen c6 phan ung voi Cu(OH)2 trong moi truong Bai8: kiem t?o thanh dung dich mau tim, trong khi Gly-Ala la dipeptit nen khong Loai A, C vi anilin khong lam chuyen mau qui tim am. CO tinh chat nay. Loai B vi amoni clorua c6 moi truong axit yeu, lam qui tim am chuyen sang ->DapanC. ^ iril rlOi:-!/! 5' • )ij»:|9q,ufi3 oifa'ift'f .vir, - • ; . mau hong. — Dap anD. > Nhqn xet: Tripeptit (mach ho) can chua 3 aminoaxit: Gly, Ala va Phe. Bai9: Co 6 loai tripeptit nhu vay: Gly-Ala-Phe; Gly-Phe-Ala; Ala-Gly-Phe; Ala- Stiren lam mat mau nuoc brom: 'K * • 366 .y,- Phe-Gly; Phe-Gly-Ala; Phe-Ala-Gly. -> Dap an A. • '^'Z '^B;-- ' '^'"^''''' ' ' . 367 Ca'iri naii'j on luyen thi dai lioc 18 chuyfen cii; Hcia lioc Mtjnyf'ii Van HSi Bail5: -CO-NH- n ^ i j = 0,02 m o l . • 's,i*tft'fiij,l li-M •dUisflt o^AtAwyid vyun GQi cong t h i i c ciia X la H2NRCOOC2H5. nx = n ^ i ^ ^ 0,02 m o l . , ^ iQ,. Im •:jiA smrnj 4 - r - , '^-ML + -Hv'A^. j j u j i U ^Qun \<>J s.i"'ub M x = 103 -> R = 1 4 ( - C H 2 - ) . ' ' " ' ,:^!v:>,: • rv,.v • > • 7a -COOH Mol: + H2N- 7a + NaOH 3a , - —> - C O O N a 3a •• • Theo bai: *' '''^^ -> D a p an B. Mol: -> - C O O N a + NaOH + H2O 5 iy-.i\a h « v ' : , i i > I J i - ' X ' M ; ' [ ' Bao toan k h o i l u g n g : "' m Bail6: nNaon = 7a + 3a = 10a = 0,3 —> a = 0,03 m o l . Nhqn xet: K h i cho cac peptit tac d u n g v o i N a O H t h i c6 cac lien ket peptit va -^m Ad'} :(3'-I) n ^ ^ i i a i l o ' ! + m K O l I = m m u o i khan + m [i^Q n h o m - C O O H (ciia amino axit dau C) t h a m gia p h a n u n g . osb «/(!.,."',_ -> D a p an C. _.||: J, = 41,04 + 0,03.3.18-0,3.56 = 25,86 gam. , pj :n«wfe'»H :, Theo bai, 2a m o l t r i p e p t i t mach h o Y c6 2a.2 = 4a m o l lien ket peptit. ;; a m o l tetrapeptit mach h o X c6 a.3 = 3a m o l lien ket peptit. Nhan xet: K h i cho cac peptit tac d u n g v o i H C l t h i c6 cac lien ket peptit va T o n g so m o l n h o m - C O O H bang a + 2a = 3a. ^ n h o m H 2 N - (ciia a m i n o axit dau N ) t h a m gia p h a n u n g . -.moh 1 y i i i Cac p h a n u n g r i i t gon ciia lien ket peptit va n h o m - C O O H la: ^, Theo bai, a m o l d i p e p t i t mach h o X c6 a . l = a m o l lien ket peptit. -CO-NHMol: 7a 3a Theo bai: > -COONa + H2N- + NaOH T o n g so m o l n h o m H 2 N - bang a + 2a = 3a. > -COONa 3a nNnon Cac p h a n l i n g r i i t gon ciia lien ket peptit va n h o m H 2 N - la: + H2O 3a = 7a + 3a = 10a = 0,6 -> a = 0,06 m o l . ^^^^^ ^ - j , ^ ^.^^y •i • ;ii • •r":''^''< ' ^ \'t^'''^-''-i(:it.,. + H C l + H2O 5a 5a H2NMol: j_rv\ = 51,72 + 0,6.40 - 0,06.3.18 = 72,48 g a m . ->DapanB. Mol: :£i + m N a O H = m m i i o i khan + m , , Q ->mn,uoikhan -CO-NH- , f t i | ' e f A - ^ f ; > : ; i ; .HV, Bao toan k h o i l u g n g : 51,72 ff\ 2a m o l t r i p e p t i t mach h a Y c6 2a.2 = 4a m o l lien ket p e p t i t 7a -COOH Mol: + NaOH Vii: r ; + HCl 3a 3a Bai 17:,,: ->m Loai A v i cac t r i p e p t i t t r o len m o i c6 p h a n l i n g m a u b i u r e (cac dipeptit + CI 5a > CIH3N- » rft hM " • Theo bai: nuci = 5a + 3a = 8a = 0,4 - » a = 0,05 m o l . Bao toan kho'i l u g n g : '(\^,"'(W)''"''"^"' > -COOH mpepiit + mHci + m = 26,9+ 0,4.36,5+ 0,25.18 = 46 gam. =m ^,, j. ^ ' ->DapanC. khong CO phan ung). L o a i B v i m a t xich d a u tien t r o n g cong thuc k h o n g p h a i la m o t a - a m i n o a x i t . L o a i C v i m u o i p h e n y l a m o n i clorua tan t r o n g n u o c . ai D a p an D . 6 d i e u k i ^ n t h u o n g , c6 4 a m i n : M e t y l a m i n , dimetylamin, j.^ - ^ t r i m e t y l a m i n va e t y l a m i n d e u la n h i r n g chat k h i c6 m i i i k h a i . Bai 18: ,V, •Jl. Nhan xct: K h i cho cac peptit tac d u n g v o i N a O H t h i c6 cac lien ket peptit v a n h o m - C O O H (ciia a m i n o axit dau C) t h a m gia phan u n g . M Theo bai, a m o l tetrapeptit mach h o X c6 a.3 = 3a m o l lien ket peptit. "fii 2a m o l t r i p e p t i t mach h o Y c6 2a.2 = 4a m o l lien ket p e p t i t T o n g so m o l n h o m - C O O H bang a + 2a =3a. ,; > ! I HI i3-3fi';i Cac p h a n u n g r i i t g o n ciia lien ket peptit va n h o m - C O O H la;,-; {||iQ 4*368 369 UiyrrafflT Ca,-n naiig on luy?n tlii 6.)\c 18 chuyeii de H6a hpc - Nguyen Van H j i Chuyen de18 H2N-(CH2)s-COOH a. C h a t d e o - -j-'Vi; ' ) (- C H o - CH2 -)n ' / ^j- t . p. xt -> !• ! Nilon-7 (to enang) -HN-(CH:)5-CO- 'CH-CH-NH n CH2 = C H > I (-CH2-CH-)n n CH2 = C H ei - '•.p.^-> (-CH2-CH-)„ Cao su t h i e n n h i e n la poliisopren [ C a o su t o n g h o p g o m : Cao su buna; cao su buna-S ( t r u n g h o p b u t a - l , 3 - d i e n CH3 v o i stiren); cao su b u n a - N ( t r u n g h o p buta-l,3-dien v o i a c r i l o n i t r i n ) . :. C A C V i D V M A U > (- C H . - C H -)„ COOCH3 '5»f} ue. oj:, Cao su g o m 2 loai: Cao su thien nhien va cao su t o n g h o p . 71 SS' P o l i ( m e t y l metacrylat): (Thuy t i n h h u u h u u co plexiglas): CHj '.,5 -.'O Caosu ' ci ' capron acrilonitrin ''•^•"^ > (- CH2 - C H -)„ n CH: = CH ta nCH.-CH-CN P o l i v i n y l clorua (PVC): - f.:.*^! CH^-CH-CO H CH: " ' ' Polistiren: - i^nang-viyi— .(jr n C H 2 = CH2 - -"S > - H N - ( C H 2 ) s - C O - + H2O H2O l Axit CO -aminoenantoic Polietilen (PE): - Nilon-6 H 2 N - ( C H 2 ) 6 - C O O H — '' 1. H E T H O N G K I E N T H l / C T R Q N G T A M uvvn > - H N - ( C H 2 ) s - C O - + H2O Axit £-aminocaproic POLIME vA VAT LIEU POLIME M I V V i d u 1: Polime d u n g de che tao t h u y t i n h h i i u co (plexiglas) d u g c dieu che COOCH3 bang p h a n u n g t r u n g h o p Nhira phenolfomandehit: A . CH2=C(CH3)COOCH3 + HCHO '-P-"' B. C H 2 = C H C O O C H 3 ti f>!:> J5 A, 1 C. C6H5CH=CH2 OH D . C H 3 C O O C H = C H 2 s!.i',i kpA!..\'i{'' > Laigiai: x of!;;!!; • M o n o m e d i i n g de che tao t h u y t i n h h i i u co la m e t y l metacrylat. .c , — D a p an A . > b. T o Vi T o g o m 2 loai: to thien nhien va t o hoa hoc 2: T r o n g so cac loai t o sau: To tam, to visco, t o nilon-6,6, t o axetat, to capron, to enang. N h i i n g loai to nao thuQC t o nhan tao ? a) To thien nhien gom: To tam, bong, len, day. A . T o t a m va t o enang. B. T o visco va t o nilon-6,6. b) To hoa hoc gom 2 loai: T o tong h o p va to ban t o n g h g p (to n h a n tgo) C. T o nilon-6,6 va t o capron. D . T o visco va t o axetat. + T o n h a n tao g o m : T o visco va to axetat. + T o t o n g h o p g o m 3 loai: T o p o l i a m i t (nilon-6,6; nilon-6; nilon-7; to capron); ^ H a i loqii t o n h a n tao t r o n g c h u o n g t r i n h la t o visco v a t o axetat. Ca hai loai t o polieste (poli(etylen-terephtalat)); to n i t r o n . B to nay deu co n g u o n goc t u xenlulozo - > Dap an D . H2N-(CH2)6-NH2 + HOOC-(CH2)4-COOH Hexametilen diamin " Lot gidi: - ^ ) Axit adipic . - H N - ( C H 2 ) 6 - N H - C O - ( C H 2 ) 4 - C O - + 2H2O Nilon-6,6 ^70 '''^ V i d u 3: K h i tien h a n h d o n g t r u n g h o p buta-l,3-dien va a c r i l o n i t r i n t h u duoc mpt loai cao su b u n a - N chua 8,69% n i t o ve k h o i l u g n g . T i le so mat xich g i i i a b u t a - l , 3 - d i e n va a c r i l o n i t r i n t r o n g cao su la • ^ ^ i , . A. 1 : 1 . . , , B. 1 : 2 . C.2:l. . : D.3:l. 371 Ill iiaiKj Oil iiiyfin tin Cty TNHH MTV IJV/VH Khang Vigt hoc W. ' iiiiygn d§ H6a hgc - Nonyuii V l n Hi\ Lai giai: i d u 6: Trong cac polime sau: (1) poli(metyl metacrylat); (2) polistiren; (3) y->A ' Cong thiic buta-l,3-dien: CH2=CH-CH=CH2 va acrilonitrin : C H 2 = C H - C N . nilon-7; (4) poli(etylen-terephtalat); (5) nilon-6,6; (6) poli(vinyl axetat), cac Goi thanh phan cao su b u n a - N la (C4H6)k(C3H3N) polime la san pham cua phan ung trung ngung la C4k+3H6k+3N ^ M = ^ - ^ ^ = 1 6 1 ^ 12(4k + 3) + 6k + 3 + 14 = 161 8,69 "• • 0',>. - > k = 2. ^DapanC. ^--'''v. . " " : ' V i d u 4: K h i luu hoa cao su thien nhien thu dugc mot loai cao su trong do luu huynh chiem 2,3% ve khoi lugng. Hoi trung binh mgt cau no'i - S - S - cong vao bao nhieu mat xich isopren? A.20. : , ^,,,,,^.1,,..B.10. f4''").|.i)=;, }"f >n i £ . r j...:,.. M= 2,3 ~ 1391 68k + 32 = 1391 . | J,, Cac polime con lai la san pham cua phan ung trung hgp. , , B. 6. Lcrigidi: D. 3. CH2=CH-C1 , A sai vi to visco la to ban tong hgp (to nhan tao). "^ ncuq. . "^ ^ ' ^ ^ ' B sai vi cao su buna-N la san pham cua phan ung trung hgp. Day la phuong Lj.'t C sai vi triing hgp stiren thu dugc polistiren - > D a p an D . , „ , ' • ^ >" ' &^'> •«.,.-'•<,:;••*•'•O'-' ,P,1,, , 1 *' ' ^"'>-ikA* •*/i-''-;;J-n> . / V • ' - . . . ' M i . ^ ^ v V'V .1,,,,:,,,, , '1, f s r ; A. T o capron; nilon-6,6; polietilen. ,>.'i ;,i.t. M ' ' - - tM' f i J ' B. Poli(vinyl axetat); polietilen; cao su buna. Thanh phan ung voi k mat xich trong mach P V C la C2kH3kClk. , C . Nilon-6,6; poli(etylen-terephtalat); polistiren. , ^ D. Polietilen; cao su buna; polistiren. Khi 1 phan tu CI2 phan ung thi 1 nguyen tu C I se vao t h e c h c cua nguyen tuH. ' . , ' ' Lai gtat: Cac polime bj thuy phan trong dung djch H2SO4 loang nong la cac polime i$o _> Cong thuc polime sau khi clo hoa: C2kH3k-iClk+i thugc loai poliamit hoac polieste. 63,96 li.gl l b ) - > 27k - 1 + 35,5(k + 1) = 55,5(k + 1) , ' •! lQf( - > 2 7 k - l =20(k + l ) - > k =3. — Dap an D . > . '"^ < Loai A vi to capron va nilon-6,6 deu thugc loai poliamit nen bi thuy phan. ^M=:?5^^-^=55,5(k.l) 372 '' D. Poli(etylen - terephtalat) dugc dieu chebang phan ung trting ngung cac la N h u a P V C la poli (vinyl clorua). Cong thuc vinyl clorua: ' V i du 8: Cac cha't deu khong bi thiiy phan trong dung dich H2SO4 loang nong C . 4. i l l 10 ' an gay nhieu cho hgc sinh. lugng, trung binh mgt phan tu clo phan ung v6i k mat xich trong mach P V C . Gia tri cua k la ' , — D a p an D . > ,^,^n V i dvi 5: Clo hoa P V C thu dugc mgt polime (to clorin) chua 63,96% clo ve khoi A. 5. Cac polime la san pham cua phan ung trung ngung la: (3), (4), (5). monome tuang ung. f'./ \ ' x(- - » k ~ 20. — Dap an A. > v: Latgtat: , ,' 1 ^,5 /'^^'^ (''^«»*'* ^ ' I , C . Triing hgp stiren thu dugc poli(phenol-fomandehit). ^ „^:y^^^^ y,,, ^ ' (3), (4), (5). B. Triing ngung buta-l,3-dien voi acrilonitrin thu dugc cao su buna-N. * Goi thanh phan cao su luu hoa la (C5H8)kS2 — CskH8kS2 , ^.j > ^ D. (1), (3), (5). A. T o visco la to tong hgp. , ,. Cong thuc isopren la: CH2=C(CH3)-CH=CH2. i'i'7i-(''yT"");"!'f:'") B.(i),(2),(3). V i du 7: Phat bieu nao sau day la dung? c o ;^ ^ ^ . ^ ^ ^ ^ . :.^^^ ^^^^ 3• ^ Cao su thien nhien la poli(isopren). • c. . .,1 ^ ^ ; , ,!,•,/'. , Loai B vi poli(vinyl axetat) thugc loai polieste nen bi thiiy phan. ' < Loai C vi nilon-6,6 thugc loai poliamit; poli(etylen-terephtalat) thugc loai polieste nen deu bj thiiy phan. v ->DapanD.: ,,u''H:h;r . . /•••>;>'.•,,' 373 Cty i W i i H MTV DWH Khang Vigt dm nang On luyQn thi d^i hpc 18 chuyen ' " '/ >H.>i(. ' •! i /i D . 1,1,2,2-tetrafloeten; p r o p i l e n ; stiren; v i n y l clorua. , •; Bai 11. C h o cac chat hoac cac cap chat sau day: nilon-6,6. So t o t o n g h g p la B.2. C.3. (1) C H 3 - C H ( N H 2 ) - C O O H ; D.4. Bai 5. N i l o n - 7 d u g c dieu che'bang phan l i n g n g u n g t u aminoaxit nao sau day? A. H2N-(CH2)6-NH2 .«eiv,,HviB. C. H2N-(CH2)6-NH2 va H O O C - ( C H 2 ) 6 - C O O H y , ,,,,, = D.CH3CH(NH2)COOH.. -..orh.rh u^irJn rm Bai 6. D a y g o m cac chat d u g c d u n g de t o n g h g p cao su Buna-S la: A. CH2=C(CH3)-CH=CH2, C6H5CH=CH2. B. C H 2 = C H - C H = C H 2 , C 6 H 5 C H = C H 2 . . . i w i d :imM C. C H 2 = C H - C H = C H 2 , S. ' ml, IBSI- A J .6 u • O : ' mf>A({ r.i>.' d 'Vuu,4 n ' T V ' " H C H O va CeHsOH; r^^ihr^hO^ (4) H 2 N - ( C H 2 ) 5 - C O O H ; (5) H2N-(CH2)6-NH2 va H O O C - ( C H 2 ) 4 - C O O H So t r u o n g h g p c6 k h a nang t h a m gia phan u n g t r u n g n g u n g tgo thanh p o l i m e la A. 2. . (ji^ (2) H 2 N - C H 2 - C O O H ; (3) :v,%k,-.M B. H 2 N - ( C H 2 ) . - C O O H ;^ ,1! i , . . : B. 1,2-diciopropan; vinylaxetilen; vinylbenzen; toluen. capron neu tren Ian l u g t la : , B. C H 2 = C ( C H 3 ) - C O O C H 3 v a H 2 N - [ C H 2 ] 6 - C O O H . mach t o capron la 17176. So l u g n g m 5 t xich t r o n g doan mach nilon-6,6 va A. 5. ^ D. CH2=CH-COOCH3 Bai 3. Phan t u k h o i cua m o t doan mach t o nilon-6,6 la 27346 va ciia m o t doan A. 113 v a 152. :-'n':.V'<>...'• A . C H 2 = C H - C O O C H 3 va H 2 N - [ C H 2 ] 6 - C O O H . B. C H 2 = C H - C O O - C 2 H 5 Bai 2. N i l o n - 6 , 6 la nriQt loai A. T o poliamit. ;,(=•• ?,'- D a p an C. •37/1 „;,„^,.(^,.^.,^^ j , Bai 3. . , ^ A . Benzen; xiclohexan, amoniac. N i l o n - 6 , 6 la loai t o p o l i a m i t - > D a p an A . , , so 375 Cty TNHH MTV DVVH Khang Vigt H6a hqc - Nguyen Van Hi\ d m nang 6n luygn thi dgi hpc 18 chuySn Bai 4. •'^ .• Nhan xet: De lam bai tap nay, hoc sinh can nho each phan loai to. ai 10. Nhqn xet: C a c monome c6 kha nan^ lham gia phan ung trimg hop can c6 ' ; Bong, to tam thuoc loai to thien nhien. lien ket C=C trong phan tu. To xenlulozo axetat thuoc loai to ban tong hop (to nhan tao). ; Loai A vi clobenzen khong c6 phan ung trung hop. T o capron, to nitron, nilon-6,6 thuoc loai to tong hop. ) > i Loai B vi 1,2-diclopropan va tokien khong c6 phan ung Uun^' hop. Bai5. • ' • , ; Loai C vi cumen khong c6 phan ung trung hop. ) i j ' . „>, "i . i , — • D a p an C . > t j ,,; , —^DapanD. ' •• ' ' ' -n* < To niIon-7 hay con goi la to enang la loai to duoc dieu che bang phan ung Luu I/: B va C la cac phuong an gay nhieu vi cac chat trong day deu c6 d u u i trung ngung axit O) -aminoenantoic (axit 7-aminoheptanoic). en, hoc sinh de lam tuong chiing c6 lien ket C=C trong phan tu. , Lu'u y: Nilon-7 la to trong mot mat xich c6 7 nguyen tir cacbon. - > Dap an A . Bai 6. ^ i . , ' "n • . f'ti aill. ic' ' Nhqn xet: De lam duoc bai nay, cac em can nam duoc dieu kien de cac i . 1 . i . t 'M1 ' ' i ' '' ' monome tham gia phan ung trung ngung la monome phai da chuc va giiia I Cao su buna-S la san pham cua phan ung trung hp'p buta-l,3-dien va stiren. Luu y: phuong an C la phuong an gay nhieu. ' Bai 7. Nhan xet'De Tat ca 5 truong hop deu c6 kha nang tham gia phan ung trung ngung. • - > D a p an B. - > Dap an B. ' ' i cac nhom chiic c6 kha nang tach nuoc. . I . I I . ' • *• ul ' ' V /M I tao thanh cao su buna-N thi Z la acrilonitrin. ' • '• • •"' - > Dap an B. ^ X la vinylaxetilen; Y la buta-l,3-dien. t " i Bai 8. Nhan xet: De lam duoc bai tap nay hoc sinh can nam duoc each thuc tong hop cac polime. Cac polime: oliacrilonitrin, poli{metyl metacrylat), polostiren duoc dieu che it* j * . i bang phan ung trung hop. Poll (etylen terephtalat) duoc dieu che bang phan img trimg etylen glicol va axit terephtalic. " ' I ' l l I i -> Dapr.nD. Bai 9: 1.' r i ; . >l I Nhqn xet: D e lam duoc bai tap nay hoc sinh can nam duoc each thuc tong hop cac polime. . ' r De de nho, hoc sinh can luu y rang: nilon-6 la to trong mot mat xich c6 6 nguyen tu cacbon. t)) . / ' j ' h I'jit, , ,,1!^ n, i.i nil. ' K".' 'J I - » D a p an D. 376, 377 T Cfiiii i:arig on luyen thi dai hoc 18 chuyeii (le H'ja hpc - N g u y j n VSn Hi\ , mi T H I T H l / DAI HOC D E S O l • Cau 1 . Cho so d o bien hoa sau ( D o n g phan cua Y) T ^ Z A . 2. B. 4. C. 1. iVr.f:'}-.. 0.3. v u a d u 170ml H N O 3 2 M , t h u d u g c 1,232 l i t N O (san p h a m k h u d u y nhat, a ^ ^ C2H2 So'thi n g h i # m xay ra p h a n u n g va giai p h o n g k h i la Cau 6. H o a tan hoan toan m g a m h o n h g p X g o m A l va F e x O y vao m o t l u g n g ' Br,(dd) Cty TNHii M i V DVVH Khang Vi?t >Y dktc) va d u n g djch Y chua hai m u o i cua hai k i m loai hoa t r i 3. Meu cho Y tac Ten cua cac chat Y va T Ian l u g t la d u n g v o i d u n g djch N a O H ( d u ) , n u n g ket tua sau p h a n u n g t o i k h o i l u g n g A . 1-brometan va 2-brometan. k h o n g d o i t h u d u g c 3,6 gam chat ran. Gia trj cua m va cong thuc F c x O y la B. 1,1- d i b r o m e t a n va 1,2-dibrometan. A. 4,83 va Fe304. B. 4,95 va Fe203. C. 1 , 2 - d i b r o m e t a n va 1,1-dibrometan. C. 4 , 9 5 v a F e O . D . 5,25 va Fe304. C a u 7. D o t chay hoan toan m g a m hon h g p X g o m 3 ancol ( d a n chuc, d o n g D. 1-brometan va 1,2- d i b r o m e t a n . dang), t h u d u g c 8,96 l i t k h i CO2 (dktc) va 11,7 gam n u a c . M a t khac, neu d u n C a u 2. Cho 2,30 g a m h o n h o p g o m A l , Fe va Z n tac d u n g v o i m o t l u g n g vua du d u n g d i c h H2SO410%, t h u dugc 2,24 l i t k h i H2 (a d k t c ) . K h o i l u g n g dung n o n g m g a m X v o i H2SO4 dac t h i tong k h o i l u g n g ete to'i da t h u d u g c la djch t h u d u g c sau phan u n g la A . 7,85 g a m . A . 102,3 g a m . B. 95,5 gam. C. 100,1 g a m . A. C H 3 - C H 2 - C O - C H 3 . . ,, C.CH=C--CH2-CHO. "tf"^ > (3) CH3COOCH=CH2 + H2O B. C H 2 = C H - C H 2 - C O O H . D. CH2=CH-CH2-CHO. (1) K h i dien tich hat n h a n tang, nhi^t d g n o n g chay ciia k i m loai k i e m g i a m dan. — ^ (2) K h i d i e n tich hat nhan tang, nhiet d g n o n g chay cua k i m loai k i e m tho I tang d a n . (3) NhCrng k i m loai co phan l o p electron ngoai cung la ns^ deu la k i m loai So'phan u n g t r o n g d o CO tao thanh andehit axetic la B.5. C.4. k i e m tho. D.2. C a u 4. Phan h u y m o t l u g n g ozon t r o n g b i n h k i n c6 d u n g t i c h 1 l i t ( k h o n g doi), (4) 6 d i e u kien t h u a n g , cac t i n h the k i m loai k i e m d e u co c u n g m o t kieu sau 40 giay t h u d u g c 0,06 m o l o x i . Toe d g t r u n g b i n h cua p h a n u n g (tinh m a n g t i n h the. theo ozon) t r o n g 40 giay tren la B. 7,5.10"^ mol/(l.s). : ' T r o n g car phat bieu tren, so phat bieu d i i n g la A . 2,5.10^ mol/(l.s). C. 1,0.10-3 mol/(l.s). ">' !au 9. Cho cac phat bieu sau: t" NaOH (5) CH3CHCI2 + N a O H A. 3. ' ^ A . 1. D . 5,0.10"^ mol/(l.s). (1) N h o d u n g d i c h H C l vao d u n g dich KHCOa. B.2. ) C.3. ^ D.4. ^S'^'f' • C a u 10. D a y g o m cac p o l i m e co thanh phan phan t r a m cac n g u y e n to bang C a u 5. Tien hanh cac t h i n g h i ^ m sau: nhaula:' ; r K > V i H>;;\ i ,t;|B:.j;:i, & • tswH../.- A . t o capron, nilon-6, t o nitron. §,.f aji) (2) Sue khi clo vao dung djch KHCO3. B. p o l l etilen, p o l l propen, p o l l but-2-en. ^•»-* I ' l (3) Sue khi O3 vao dung dich K I . C. to enang, to capron, nilon-6,6. (4) Nho dung djch K H C O 3 vao d u n g djch K H S O 4 . 378 D . 5,60 g a m . 11,2 l i t k h i o x i (dktc). C o n g thuc cau tao cua X la (1) CH3CH2OH + C u O (4) CH2=CH2 + O2 C. 6,50 gam. lau 8. Do't chay hoan toan 0,1 m o l chat h i i u co X mach h o can d u n g v u a d u D . 97,8 g a m . C a u 3. Cho cac p h a n u n g sau: (2) H C ^ C H + H 2 O B. 7,40 g a m . m , -jiusi' : D . p o l l etilen, cao su thien nhien, cao su buna. •i •<•'>• 1 i - = ' , 379 C^m nang 6n luy^n thi d^i hpc 18 chuy§n d§ H6a hgc ^iiiuvcii van Hii Cty TNI Hi iVlTV DVVH KhangVift Cau 1 1 . Dot chay hoan toan 14,12 gam ba axit beo: stearic, oleic va linoleic, sau au 17. Cho hon hgp bot gom x mol A l va 0,1 mol Zn tac dung voi 500ml dung phan ung thu duoc 20,16 lit C O 2 (dktc) va m gam H2O. Gia trj ciia m la dich FeCla 0,32 M , sau phan ung thu dugc 11,56 gam hon hgp .2 kim loai va A. 14,12. dung dich Y. Gia tri ciia x la ,r , .jv B. 16,52. C. 15,48. . , D. 17,12. Cau 12. Hon hgp M gom hai hgp chat huu co X va Y mach ho, deu c6 cong thuc phan t u la C4H9CI, Khi thuc hien phan ung tach H C l trong dieu kien ^ , B. 0,06. i '> D. 0,10. IV':,'f- •'• 1 \ (4) Glucozo va saccarozo bi thuy phan cho san pham co phan ung trang ioG - oov ;* ' (3) Glucozo va saccarozo deu k h u dugc AgNOs/NHs khi dun nong. f>/Ifiv", D. l-clobutan va 2-clo-2-metylpropan. , ;Tu:i<*:jTr.'n6Gi, n e o f i ;(jiih Cau 13. Cho cac phat bieu nao sau: ^{qX'rf au 18. Co mot so nhan dinh ve cacbohidrat: lam. ' C. 0,12. i^-'^'^ (2) Glucozo va saccarozo hoa tan Cu(OH)2 tao thanh dung dich mau xanh ,., B. 1-clobutan va 2-clobutan. C. l-clo-2-metylpropan va 2-clobutan. ••'•'^''i •'•••••'•A (1) Glucozo va saccarozo deu, la chat ran, co vj nggt va de tan trong nuoc. thich hgp chi thu dugc duy nhat mot anken. X, Y co ten ggi la A. l-clo-2-metylpropan va 2-clo-2-metylpropan. A. 0,14. •.'^•••f •'t{A'fM''t !ii : f ' I M ! U A ( V :$^#tj)t)'<:*3 gUOng. h (1) K i m loai xesi thuong dugc dung lam te bao quang dien. (5) Glucozo va fructozo deu tac dung voi hidro (xuc tac N i , t°) tao ra sorbitol. (2) Hgp kim Na - K dung lam chat trao doi nhiet trong mot so' 16 phan ling (6) Xenlulozo va tinh bot deu la polisaccarit. ; .t, (3) Kim loai kiem thuong dung de che tao hgp kim dung trong k l thuat hang khong. . .rH j ^) ) -u (4) K i m loai Na dung de san xuat muo'i an cong nghiep. Trong cac phat bieu tren, so phat bieu dung la B. 4. jj ) /rjj'i ( n l n C.2. J-'H B. (1), (2), (5), (6). C. (1), (2), (4), (5). D. (1), (2), (3), (6). 0,045 mol CO2. Cac andehit trong hon hgp X la A. C H 3 C H O va HCHO. B. C2H3CHO va C H 3 C H O . C. C2H3CHO va HCHO. D. C2H5CHO va HCHO. !au 20. Cho cac phan ung sau: D. 336. Cau 15. Dung djch X chua AlCb y M va Al2(S04)3 zM. Lay 400 ml dung djch X t A. (1), (3), (5), (6). tac dung voi 300ml dung dich NaOH 2,04M, sau phan ung thu dugc 8,424 l . F e S 2 + 02 3. HgS + O2 '" 5. SO2 + Br2 + H2O BaCh (du), thi thu dugc 33,552 gam ket tua. Ti so y : z la 7. KNO3 B.0,73». ; C.2,00. D. 1,75. 2. Cu(N03)2 '" > gam ke't tiia. Mat khac neu cho 400ml dung djch X tac dung voi dung dich A. 0,50. ,, mol A g va dung djch Y. Toan bo Y tac dung v6i axit HCl (du), thu dugc D .3 . dugc Vml khi CO2 (dktc). Gia trj cua V la: C. 560. :) toan voi dung dich AgNOa trong NH3 (du), sau phan ling thu dugc 0,195 f j a d , dung djch axit X nong do 0,1M phan ung het vai dung djch NaHCOs, thu B. 224. \ lau 19. Cho 1,770 gam hon hgp X gom 2 andehit don chuc phan ung hoan ^ t, Cau 14. Axit cacboxylic X co cong thuc don gian nhat la C3H3O2. Khi cho 100ml A. 448. . Nhi>ng nhan djnh dung la hatnhan. A. 1. ^ . 4. H2S + SO2 ) )• 6. Ag2S + O2 8. NH4NO2 . '" ) So phan ung tao ra dan chat la Cau 16. Sue 3,136 lit khi CO2 (dktc) vao 500ml dung dich NaOH 0,32M. Sau A. 5. B. 3. C. 6. D. 4. phan ung thu dugc dung dich X. Cho 250ml dung dich Y gom BaCh 0,32M au 21. Cho 1,344 lit khi CI2 (dktc) di qua 250ml dung dich K O H a mol/1 6 va Ba(OH)2 y M vao dung djch X, sau phan ling thu dugc 7,88 gam ke't tua 80"C. Sau khi phan lirig hoan toan, thu dugc 3,725 gam KCl. Gia t r i cua a la va dung djch Z. Gia trj cua y la A. 0,24. A. 0,03. rf i i o q ,ft^.qoiq . B.0,08. - C.0,05. , ,> ,, ,,; , D . T h o i tix tit h o n h o p k h i X vao nuoc v o i t r o n g d u . C. Tat ca cac p e p t i t deu tac d u n g v o i Cu(OH)2 t r o n g m o i t r u o n g k i e m cho hgp chatmau tim. ^ !j ftm>q n'.it , • D . Cac p e p t i t k h o n g ben t r o n g m o i t r u o n g axit hoac bazo. 2iu 29. H o n h g p X g o m propen va H2 co t i k h o i so v o i H2 bang 13,0. N u n g Cau 23. D e san xuat 1 tan xa p h o n g chua 72% k h o i l u g n g n a t r i stearat, can bao n o n g X (co N i xiic tac), t h u dugc h o n h g p Y. Sue Y v a o n u o c b r o m ( d u ) , n h i e u k g chat beo chua 89% k h o i l u o n g tristearin (con 1 1 % tap chat tro)? thay C O 14,4 g a m b r o m phan u n g . N e u do't chay het Y r o i h a p t h u toan b g A . 874,3 k g . san p h a m chay vao d u n g djch Ca(OH)2 (du), t h i thay k h q i l u g n g d u n g djch B. 784,3 k g . C 774,3 k g . D . 698,0 k g . Cau 24. H a i day cac chat sau: g i a m 15,3 g a m so v o i b a n d a u . H i ^ u suat ciia p h a n u n g cgng h i d r o ciia Day X: H2NCH2CC)OH, CH3NH2, C6H5NH2 (anilin), CH3COOCH3. D a y Y: D u n g d i c h H C l , d u n g d i c h K O H , nuoc Br2, CH3OH (xiic tac). , p r o p e n la A . 50,00%. Cho Ian i u o t cac chat thupc day X tac d u n g v o i cac chat 6 day Y . So phuong ' t r i n h phan ling xay ra la A . 7. , B. 9. jiujui C.8. D.6. , Cau 25. Che 0,26 gam axetilen tac d u n g v o i H C l ( d u ) xuc tac thich h g p , thu ''SV; irA ,>c','J'HJI « ' i v B. 33,33% r ? ? f ) ! C. 60,00%. ";;i„ „ D . 40,00%. Cau 30. D o t chay hoan toan 2,6 g a m h o n h g p X g o m e t y l axetat, v i n y l axetat va m e t y l acrylat, t h u d u g c 2,688 l i t CO2 (dktc) va m o t l u g n g nuoc. N e u t h u y phan hoan toan 2,6 g a m X t h i can bao nhieu m l d u n g djch K O H 0,15M? A . 200. B. 150. C. 100. D . 300. d u g c d a n xuat halogen X. T h u y phan hoan toan X t r o n g m o i t r u o n g K O H , dun n o n g , sau p h a n u n g t h u d u g c chat hihi co Y va d u n g djch Z . A x i t hoa 0,3M va H N O 3 I M , t h u d u g c V l i t k h i N O (san p h a m k h u d u y n h a t ) . T r g n d u n g d j c h Z bang axit HNO3 va cho tac d u n g v o i d u n g djch A g N 0 3 (du), ' Cau 3 1 . C h o 3,2 g a m hSn h g p b g t C u , A g vao 20ml d u n g d j c h X chua H2SO4 V l i t N O t h u d u g c 6 tren v o i 0,1 m o l oxi, t h u d u g c h o n h g p k h i Z , hap t h u Z t h u d u g c 2,87 g a m ke't tiia trang. K h o i l u g n g chat h i r u co Y t h u d u g c la A . 0,46 gam. B. 0,44 gam. C. 0,88 gam. D . 0,92 gam. Cau 26. D u n g d i c h X chua 0,015 m o l Fe-^ x m o l Al''*, 0,025 m o l SO42- va y mol C h C h o 710ml d u n g d j c h Ba(OH)2 0 , l M vao d u n g djch X, sau phan u n g thu d u g c 9,224 g a m ket tua. Gia trj cua x va y Ian l u g t la A . 0,030 va 0,045. D . 0,050 va 0,085. H2SO4, Na2S04. D a n h so ngau nhien (1), (2), (3), (4). K e t qua t h ; n g h i e m : (1) tac d u n g v o i (2) co ket tua; (2) tac d u n g v o i (3) co ket tiia; (2) tac d u n g v6i (4) C O ket tua; (1) tac d u n g v o i (3) co siii bgt. D u n g d i c h BaCh v a Na2S04 theo t h u tu" d u n g t r o n g I g d u g c danh so la B. (2), (3). C. (2), (1). D . (4). (2). Cau 28. Phat bieu nao sau day sai? A . Protein d o n gian k h i t h u y phan chi t h u d u g c h o n h g p cac a - a m i n o axit. B. M o t so protein tan t r o n g n u o c tao thanh d u n g djch keo va h\g t u kh' d u n nong. • t : , 382 B.4. C. 3. D.2. Cau 32. Xa p h o n g hoa hoan toan 0,1 m o l este X d o n chuc mach h o bang 80ml d u n g d i c h h i d r o x i t cua k i m loai k i e m (co nong d g 11,2% va d = 1,25 g/ml), C O can d u n g d i c h sau phan u n g , n g u n g t u , t h u d u g c 93,4 g a m chat long va ;,,,..> ,< A . C2H.COOCH3. Cau 27. C o 4 Ig hoa chat chua 4 d u n g djch rieng biet m a t nhan: BaCh, Na2C03, A . (2), (4). A . 1. 15,4 g a m chat ran khan. Cong thuc ciia X la B. 0,050 va 0,045. C. 0,030 v a 0,085. vao nuoc, t h u d u g c 800ml d u n g djch axit co p H bang y . Gia t r j cua y la B. CH3COOC2H5. C. CH3COOC3H7. D . C2H5COOC2H5. oaftttio, au 33. H o a tan hoan toan 2,68 g a m h o n h g p X g o m C u v a A g vao axit HNO3 loang, t h u d u g c d u n g d i c h Y va 448ml k h i N O (san p h a m k h u d u y nhat, 6 dktc). C h o 1,6 g a m b g t C u vao d u n g djch Y, sau k h i p h a n u n g xay ra hoan toan t h i t h u d u g c 224ml k h i N O (san p h a m k h u d u y nhat, 6 dktc), m g a m chat r a n va d u n g d i c h Z . Gia t r i ciia m la A . 1,94. B. 2,16. C. 1,40. D . 2,36. - = au 34. H o a tan hoan toan 2,42 g a m hai m u o i cacbonat cua k i m loai k i e m va k i m loai k i e m t h o vao d u n g d i c h H C l d u , t h u d u g c d u n g djch X va 0,448 l i t k h i (o dktc). Co c^n X d u g c m g a m m u o i khan. Gia t r i ciia m la A . 2,20. B.2,64. C. 2,30. s..,. D . 2,34. 383 Cam iiaiHi o'l luyfiii Itii (iai lioc; 18 cliiiyeii ciS iliia lioc Mguy§n VSn HJi Cty TNHH M T V DVVH Khang V i j t Cau 35. C h o rnxac clo (loang, v u a d u ) vac d u n g dich X chiia K F , K C l , K B r . Saq ;au 42. C h o cac chat: toluen, stiren, benzen, p r o p a n , axit metacrylic, etilen, k h i phan u n g xay ra hoan toan thu duoc durr,; djch Y chiia h o n h o p cac I axeton, p r o p a n a l , b u t a d i e n . So chat l a m m a t m a u d u n g d i c h K M n 0 4 (6 dieu muo'i, CO kho'i l i r o n g bang 88,875% k h o i l u g n g m u o i chua t r o n g X. Thanh k i f n t h i c h h g p ) la phan p h a n t r a m k h o i l u g n g K B r c6 t r o n g X la A . 25,750%. B. 29,750%. A . 7. €.11,125%. D . 11,588%. A . N u a c brom, H2 (Ni,t"). , .^plgjjy::{i C. H 2 ( N i , t°), A g N 0 3 / N H 3 . f • ><* 'I (2) X, Z la 2 d o n g v i cua c i i n g m o t n g u y e n to'hoa hoc. (3) X va Z CO Cling so kho'i. X p h a n u n g v o i m o t l u g n g d u d u n g d i c h K O H loang n o n g , t h i t h u d u g c „,^if. D . C H 3 O H / H C I , AgN03/NH3. (1) X, Y thuoc c u n g m g t n g u y e n to hoa hpc. \M^tji, (4) X va Y CO c u n g so n a t r o n . -o'.,- .(* « n- B.2. d u n g v o l d u n g d i c h A g N O s 2 M t r o n g NH3, d u n n o n g t h i d u n g vira het r I* 8 B. H C = C - C H 2 - C H O . D. HC=C-CH2-C=CH. C3H7O2N. Chat X tac d u n g d u g c v o i axit H C l va v o i d u n g d i c h k i e m . Co A . 3. B.4. , , . , ; , , C.5. " . - - - i . . vacxin; (6) p r o t e i n ; (7) heroin. So chat co kha nang gay ki'ch thich, l a m te liet Cau 4 1 . Phat bieU nao sau d a y dung? B. 3. C.2. " , 'D.4?S | (1) Sue k h i CI2 vao d u n g d j c h K O H . I (2) Sue SO2 vao d u n g d j c h b r o m . (3) C h o SO2 tac d u n g v o i Ca(OH)2. (4) Sue k h i H2S vao d u n g d j c h SO2. (5) Sue H2S vao d u n g d i c h FeCb. (6) C h o C u O tac d u n g HNO3. Cac p h a n u n g o x i hoa k h u la A . (2), (3), (4), (6). B. (1), (2), (4), (5). C. (1), (2). (3), (5). D . (1),(2), (4), (6). (dktc) va d u n g d j c h X chua 1,62 g a m chat tan. Gia t r i ciia m la: A . 1,26. B. 1,28. Cau 47. Phat b i e u nao sau d a y diing? C. 1,62. si «»i D . 0,94. ^ B. Phenol tac d u n g d u g c v o i d u n g d j c h K O H va d u n g d i c h K H C O 3 . C. Cac chat co cong thuc p h a n t u CsHsO phan u n g v o i C u O n u n g n o n g , deu t h u d u g c an debit. day than k i n h va co kha nang gay nghien la B.5. A . 5. _ A . M g i h g p chat co chua v o n g t h a m va n h o m O H deu d u g c ggi la phenol. D.2. Cau 40. C h o cac chat sau: (1) m o c p h i n ; (2) cafein; (3) n i c o t i n ; (4) cocain; (5) A . 3. ' Cau 46. C h o m g a m h o n h g p L i , N a , K vao n u o c ( d u ) , t h u d u g c 0,448 l i t k h i H2 Cau 39. Chat X mach h o , d i e u k i e n t h u o n g 6 the r a n , co cong thuc phan tii , kien). So chat thoa m a n v o i t i n h chat ciia X la D.4. t h u d u g c 17,6 g a m C O 2 va 3,6 g a m H 2 O . M a t khac, n e u lay 0,2 m o l X tac bao nhieu chat p h i i h g p v o i X? D . 7,85. ' Cau 45. C h o cac p h a n u n g xay ra a d i e u k i e n t h u o n g : Cau 38. Chat h i r u co X mach ho, chiia C, H , O. D o t chay hoan toan 6,8 gam X C. C H 3 - C = C - C H O . C9,75. m?•..[..: p h a n u n g t h u d u g c the tich k h i CO2 bang 3/4 the tich h o i n u o c (a c i i n g dieu Off s C. 1. 300ml. C o n g t h i i c cau tao cua X la B. 18,84. '^'i Cau 44. Do't chay h o a n toan m o t ancol X mach h o (chi chiia chuc - O H ) , sau urft ,,|Blt'«-» jr^t^n SrsVBXmf A. HC=C-CHO. A . 11,90. ' T r o n g cac p h a t bieu tren, so phat bieu d u n g la A . 3. 4,48 l i t k h i H2(dktc). Gia t r j c i i a m la ^ :fVii^^^M^:' ' I fMOiff^^i D . 6. ( d u ) , t h u d u g c 18,3 g a m h o n h g p AI2O3 v a Z n O . M a t khac, n e u cho 0,15 m o l B. N u o c b r o m , AgN03/NH3. Cau 37. C h o cac phat bieu s a u ve cac nguyen t u ]l X, H Y, fj Z? C. 5. ^ a u 43. H 6 n h g p b g t X g o m A l , Z n . D o t chay hoan toan m g a m X t r o n g oxi Cau 36. Glucozo c6 t i n h k h u k h i tac d u n g v o i tat ca cac chat t r o n g d a y nao? , B. 4. C.6. D.4. v f <,(f,j A. Cac h g p chat i o n d a n d i e n tot 0 m g i trang thai v a t l i . D . Pheno! l o n g tac d y n g v o i a n h i d r i t axetic t h i t h u d u g c p h e n y l axetat. .{r,(i|; / / i^l^ ' B. Cac chat co l i e n ket cgng hoa t r i , k h o n g tan t r o n g nuac, tan nhieu trong i! bt' d u n g m o i h i j u co. Cau 48. D o t chay hoan toan 20,6 g a m 1 aminoaxit X mach ha, co n g u o n goc t r o n g thien n h i e n va chua m o t nguyen t u n i t o t r o n g p h a n t u can d i m g 23,52 l i t k h i o x i . Sau p h a n u n g t h u d u g c 16,2 g a m n u o c va 20,16 l i t h o n h g p g o m IN2 va CO2 (biet cac the tich deu d o 6 dktc). Ten ggi ciia X la ••fifir;) ;: C. Cac h g p chat ion t h u o n g co nhiet do nong chay, nhiet d o soi thap. A . axit 4-aminobutanoic. B. axit 2-aminopropanoic. D . O trang thai n o n g chay, cac h g p chat ion co k h a nang d a n dien. C. axit 2-aminobutanoic. D . axit 2-amino-3-metylbutanoic. 385 Cjiii (lai lipc 18 chiiyen de Wod tua: [i:in(] 0 1 ! Cty TNHH MTV DVVH Khang Vi?t fjquyln VSn Hii C a u 49. Tron 0,30 mol H2 voi 0,3 mol brom dun nong voi xiic tac, sau mpt thoj , gian thu dvtgc hon hop san pham Y , hoa tan Y vao 287,85 gam nude thu dugc dung dich Z , lay 100 gam dung dich Z tac dung voi dung dich A g N O , . (du), sau phan ling thu dugc 9,4 gam ket tiia. Hieu suat ciia phan ung to'ng ' hgpHBrla . A.60%. / B.30%. C.50%. < ; . D . 40%. C a u 50. C h o 5,2 gam bot Z n vao dung dich chua 0,06 mol F e C h v a 0,02 mo] C u C h . Sau khi phan ling ket thiic thu dugc chat ran X v a dung dich Y . Co ; ^ , A . 10,88 gam. B. 12,36 gam. C . 14,69 gam. (4) 2CH2=CH2 + 02 — ^ 2CH3CH0 (5) CH3CHCI2 + 2NaOH D. 11,96 gam. Theo phan ung: 2O3 ^ f,j„ > 3O2. Sau 40 giay, so mol O3 bi phan huy la 0,04 mol. Vay nong do oxi giam sau 40 giay la 0,04 mol/1. Vay toe dg phan ung Cau 5. C h g n B . (2) Cl2 + H2O ^ • > K C l + CO2 + H2O 3B 4C 5B 6A 7D 8D 9B lOB lie H C l + KHCO3 12A 13D 14A 15D 16D 17C 18B 19C 20c 22A 23B 24C 25B 26C 27A 28C 29C (3) O3 + 2KI + H2O 21B 30A 31D 32B 33C 34B 35B 36B 37C 38B 39B 40B 41D 42D 43A 44A 45B 46D 47D 48C 49C 50C > .p'M^iJ'' m K i g '(Bfi-X' '"Vi-ni •'"ir;"'!.' rr.p > HCl + HCIO 2C GQI Y GIAI DE so 1 . ' , ' ' IB > K C l + CO2 + H2O > O2 + 2KOH + I2 (4) K H C 0 3 + KHSO4 > K2SO4 + CO2 + H2O Hiiiih j i#> Cau 6. Chgn A . ; 1' u , Gpi so mol trong Y : A1(N03)3 = a; Fe(N03)3 = b. Bao toan nguyen to N ta c6: 3(a+b) + 0,055 = 0,34. Cho Y + N a O H du, thu dugc ket tiia Fe(OH)3, A l ( O H ) 3 luong tinh, tan trong N a O H d u . Vay 3,6 gam cha't ran la Fe203, suy ra b = 0,045; a = 0,05. - aiv-iS|,4:,iLlKf:M Z la CH2=CH2 nen T la CH2Br-CH2Br. Theo so do, X la CH3-CH3, Y la dong ..;;,..>,,) * • Loai A vi khi cho Z + Br2 (dung dich) se tao ra T la dan xuat dibrom. Loai C vi khi X (CH3-CH3) dugc the 2 H bang 2Br thi se u u tien the tai ciing mgt vi tri cacbon. Loai D vi Y va T la dong phan, nen cung so lugng nguyen tu brom. C a u 2. Chgn C . Khi X + H N O 3 : so mol electron do A l nhuong (-0,05x3) + so'mol electron do FexOy nhuang = 0,165. - > Khoi lugng dung dich H2S04 = 0,1.98.100/10 = 98gam. i.r • ;• Vay so mol electron do FexOy nhuong = 0,015 = so mol FexOy. Bao toan Fe ta c6: 0,015xx = 0,045 x = 3->Fe304 yujtu 'M tmt:m - H toraV& VIJ ' m = 27.0,05 + 232.0,015 = 4,83 gam. , i u 7. Chgn D. , ; fn m k'ft: ; So mol H2O = 0,65 mol > so mol CO2 = 0,40 mol nen 3 ancol deu no. Tong so mol ancol = 0,65 - 0,40 = 0,25 mol. So mol H2 = 0,1 ^ So mol H2SO4 = 0,1 f CH3CHO + 2NaCl + H2O ' DAP AN DE SO 1 phan cvia T nen Y la CHBr2-CH3. '^''•%::ff;:^^ Cau 4. Chgn C . (1) H C l + KHCO3 C a u l . ChgnB. ' trung binh tinh theo ozon la 0,04/40 = 1,0.10-^ mol/(l.s). fit". can dung d}ch Y thu dugc bao nhieu gam chat ran khan? (3) CH3COOCH=CH2 + N a O H — - — > CH3COOH + CH3CHO 1 J f;. i),.:i, C.H2„.iOH + ^ 0 2 - J ^ nC02 + („^i)H20^^''"'"^-^^'"^^ ' Khoi lugng dung dich sau phan ung = 98 + 2,3 - 0,1.2 = 100,1 gam. C a u 3. C h g n B - ^'un-m65 (1) CH3CH2OH + C u O (2) H C ^ C H + H2O 386 i"::?-' • CH3CHO + C u + H2O 80"C • CH3CHO > 0,40 /.ot - > Tong khoi lugng ancol = 10,1 gam. r'",li'it: Trong phan ung ete hoa: m.mcoi = mete+ mniroc —> 10,1 = mete + 0,25.18 - > mete = 5,60 gam. ; Cam naiiy on iuyen tin dai hyc 18 chuyen di H6a hgc - NIguySii V i n liai C dung v i kim loai kiem nhe, kiem thuong dung de che tao hop kim dimg Cau8. ChQnD. Cac hop chat deu c6 4 nguyen tu C —> So'mol CO2 = 0,40 mol. trong Id thuat hang khong. D khong dung vi muoi an thuong dupe san xua't t u nuoc bien hoac khai Bao toan nguyen to'O: - thae t u cac mo muoi. Trong cac phuong an A, C, D (cac chat c6 chua 1 oxi): 0,1.1 + 0,5.2 = 0,4.2 + so mol H2O - > so mol H2O = 0,3 mol - > X chua 6H - > Dap an D. I'l Cong thuc phan t u ciia X dang C3nHsn02n hay C2nH4n(COOH)n. Trong cac phuong an B (chat c6 chua 2 oxi) : 0,1.2 + 0, 5.2 = 0.4.2 + so'mol H2O - > so mol H2O = 0,4 mol - > X chua 8H: loai ^ Tac6:4n<2.2n + 2 - n „ , (1) Diing vi cac kim loai kiem deu c6 cung cau true tinh the. Nhiet dp nong (2) Sai vi cac cac kim loai kiem tho khong c6 cimg cau triic tinh the. Nhiet dp nong chay khong bien doi mot chieu. -> C4H8(COOH)2: thich hpp. > C4H8(CC)ONa)2 + 2CO2 + 2H2O C4H8(COOH)2 + 2NaHC03 ; ^ > n<2. -> C2H4-COOH (loai); n = 2 n =l Cau 9. Chon B. chay giam dan theo chieu tang ban kinh nguyen tu. u • Cau 14. Chpn A. Vay, the tichC02 = 0,02.22,2 = 0,448 lit = 448ml. , Cau 15. Chpn D. Truoc het ta tim z: Ba2* + SO^" )• BaS04. So mol BaS04 = 3z.0,4 = (3) Sai v i cac kim loai kiem tho ngoai c6 lop electron ngoai ciing la ns^, can 0,144 CO lop v6 electrron ben trong la ciia khi hiem. (4) Dung vi cac kim loai kiem tho khong c6 cung mot cau true niang tinh the So mol Al(OH)3 = 0,108; so mol NaOH da dung = 0,612 > 3.0,108 nen xay ra 2 phuong trinh: dang lap phuong tam khoi. Cau 10. Chon B. z = 0,12. • /-J- •* .j.;..•..'->.•..„-•;.,..A..:. Cac polime c6 thanh phan phan tram cac nguyen to' bang nhau khi cac 3' monome c6 cung cong thuc don gian nha't. O dap an B, cac polime deu c6 thanh phan don gian nha't la CH2. Cau 11. Chon C. Truoc het, can nhan thay rang ca 3 axit tren deu c6 18 nguyen t i i C trong ? ? phan tir. Vay, tong so mol axit = (1/18) so mol CO2 = 0,9/18 = 0,05 mol. Cac • axit tren deu don chuc nen so mol 0 = 2 so mol axit = 0,10 mol. Vay so mol H = (14,12 - 0,9.12 - 0,10.16) = 1,72 mol. Suy ra so mol H2O = 0,86 mol va m = 0,86.18 = 15,48 gam. Cau 12. Chpn A. + 30H- > Al(OH)3 va Al(OH)3 + OH" > A l O j + 2H2O , Vay: so'mol OH- = (0,4y + 0,8z)x 3 + (0,4y + 0,8z - 0,108) x 1 = 0,612 - > y = 0,021. U',piS^ ' -aul6.ChpnD. So mol trong X: Na* = 0,16; HCO ^ = 0,12; CO ] ' = 0,02. . So mol trong Y: Ba^* = 0,08 + 0,25y; CI" = 0,16; OH" = 0,5y. _ |+ Trpn Y vao X xay ra 2 phan ung: Hco: + OH- -> col' + va Ba2*+ CO;' — > BaC03 H2O So mol BaCOs = 0,04 mol Ta loai ngay C va D vi khong cung khung mach cacbon. So mol CO 3 ' =0,04 Loai B vi khi 2-cIobutan tach HCl tao thanh 2 anken khac nhau. 0,02 + 0,5y = 0,04 Cau 13. Chpn D. A diing vi Cs c6 electron hoa tri lien ket yeu voi hat nhan neii dupe dung lam te bao quang di^n. B dung vi hop kim Na - K c6 nhiet dp nong chay thap nen dung lam chat trao doi nhif t trong 16 phan ung hat nhan. y = 0,04. •o:dM w -1.:.-.. c:Oi.-' Cau 17. Chpn C. Hon hpp gom 2 k i m loai A l het (neu A l d u se thu dupe 3 kim loai). V$y hai kim loai la Zn d u va Fe. Mat khac, vi Zn d u nen FeCls bj k h u he't thanh Fe. Vay so mol Fe = 0,16 mol. Suy ra so'mol Zn d u = (11,56 - 0,16.56)/65 = 0,04 mol. -• ^V.'" . • 389 ca'rn nang On luyjn thi dgi hpc 18 chuygn 66 Ho.i iioi, Cty Tl\i, NguyfnVan Hii Bao toan electron: so' mol electron A l va Z n nhuang = so' mol F e C h nhan 3x + 0,06.2 = 0,16.3 - > x = 0,12. CaumChonB. " , , =0,24mol/l. ' /«'M^'Ov^^i • --^ • Cau 22. C h g n A . --uc'v-; ?, K h i N H 3 phan cue nen khi nen va lam lanh se hoa long, trong khi do H2 va Tap trung vao nhan dinh (1) v a (6) do xua't hien nhieu nhat. D e nhan thay N2 van a trang thai khi ngay rang (1) v a (6) dung — loai C . > > tach dugc NH3. Vi saccarozo khong k h u dugc AgN03/NH3 va Cu(OH)2 khi d u n nong nen Loai B v i N H 3 se tac dung voi H2SO4 dac. (3) khong dung —> loai A, D . Loai C vi H2 v a N H 3 se tac dung voi C u O . (3) Khong dung vi saccarozo khong khir dugc AgN03/NH3 khi dun nong. (4) Khong diing v i glucozo la monosaccarit nen khong c6 phan u n g thuy phan. > CO2 nen Y chiia muoi cacbonat Do Y + H C l ' , f nuoc). '" > 2 C u O + 4 N 0 2 + O2 '" ) H g + SO2 Cau21.Chon A. > 5KC1 + KCIO3 + 3H2O Mol: 0,03 0,06 <- 0,05 0,01 0,01 •i •'•'^m ilur )• A g C l + KNO3. 0,02 a taO . 1 . 0,02 Theo dinh luat trung hoa dien: 0,015.3 + 3x = 0,025.2 + y ^ 3x = y + 0,005. C h i C O dap an C thoa man. . . 3Cl2 + 6 K O H 0,01 -> C H 3 - C H O (Y) Cau 26. Chgn C . '" > 2KNO2 + O2 N2 H- 2H2O (mol): > CH3-CHCl2(X) . t o oCT Khoi lugng chat hiiu co Y = 44.0,01 = 0,44 gam. > H2SO4 + 2 H B r > 2Ag + SO2 '" ) HC^CH I (mol): '"'^ , ^ ^"P*^-^-O? n4n Sod6phanung:'*^'«'«'«'' K C l (Z) + A g N O s ' ;, ' Cau 25. Chgn B. 1 1.4FeS2 + 1 1 0 2 . _ i ! _ > 2Fe203 + 8SO2 8. NH4NO2 * C H 3 C O O C H 3 tac dung duoc voi: H C l , K O H . trinh then cho't la 3 va 6. 7. 2KNO3 ^"^ C6H5NH2 (anilin) tac dung dugc voi: H C l , dung djch Br2. 4. 5); lop 11 (2, 7, 8) va lop 12 (3, 6). Trong do can l u u y den cac phuong 6. Ag2S + 0 2 . CH3NH2 tac dung dugc voi: H C l . Day la mot cau hoi If thuye't tong hgp, c6 lien quan den kien thuc lop 10 (1, 5. SO2 + Br2 + 2H2O Mtom H 2 N C H 2 C O O H tac dung dugc voi: H C l , K O H , C H 3 O H (xuc tac). C a u 20. C h g n C . 3S + 2H2O . 3 nOfi:) „ « .;r, " Khoi lugng chat beo can diing = 0,7843.890.100/89 = 784,3 kg. I Vay andehit con lai la C H 2 = C H - C H O . • ) " •' Vay so kmol chat beo = 0,7843 kmol. Khoi lugng phan tu andehit = (1,770 - 30.0,045)/0,0075 = 56. 4.2H2S + SO2 ' ' N;>iuih<, -^^m ''^^^f^ixv*. ''^ C a u 24. Chgn C . So mol andehit con lai = (0,195 - 0,180)/2 = 0,0075 3. H g S + O2 » ' So kmol xa phong tao thanh H 1000.0,72/306 = 2,3529 kmol. (Ci7H35COO)3C3H5 + 3 N a O = > 3Ci7H35COONa + C3H." ' ^ Cau 23. Chgn B. Caul9. ChgnC. 390 TV DVVH Khang Vigt -Cau 27. Chgn A . ' ' '•S'"*''''"' V i (1) tac dung voi (3) c6 sui bgt nen (1), (3) la Na2C03, H2SO4. V i Ig (2) tac dung v a i cac Ig (1), (3), (4) con lai deu tao thanh ket tiia - > lo (2) la B a C h . Vay Ig (4) la Na2S04. ' ^ *'' L'a'n: n, ng On luyen ihi dai ligi; 18 chuyfin de Hoa hpc Cty TNHH M i V [)\/VH Khang Vigt Nguyfit Van HSI au 32. Chpn B. Cau 28. Chon C . A diing: protein duoc chia thanh 2 logi, 1-protein don gian la loai protein Goi kim loai kiem la M . Kho'i lugng dung djch M O H bang 80.1,25 = 100 gam ma khi thiiy phan chi cho Hon h^p cac a-amino axit, 2-protein phuc teip —> Khoi lugng M O H bang 11,2 gam, khoi lugng dung moi = 88,8 gam. loai protein duoc tao thanh tu protein don gian cong vai thanh phan "phj Ta CO phan ung: protein" n h u axit cacboxylic, chat beo,... RCOOR' + M O H B diing, v i du long trang trung tan trong nuoc, khi dun soi thi long trang trung dong tu lai. C sai vi chi cac peptit c6 3 mat xich tra len moi c6 phan ung mau bioure. D diing vi lien ke't peptit de bi thiiy phan trong moi truong axit hoac bazo. Cau 29. Chon C . T u ti khoi suy ra ti I f mol CsHe: H2 = 3 : 2. 0,1 a n-jsO >RCOOM + R'OH 0,1 . .>i.rj :.tj':.«..i ui/x uiiA l''^\U'i'^id'%dUJ\o:J'^'•••.? Trong 93,4 gam chat long c6 88,8 gam n u o c con lai la ancol d _> Khoi lugng ancol = 4,6 gam ^ ' • ffifta fi^ifD .Tf if; Khoi lugng phan tu dia ancol R ' O H = 46 ^ R' la C2H5-. ( ' RCOOC2H5 = 88 ^ R la CH3-. ,j Cau 33. ^ - > So mol C3H6 phan ung = so'mol H2 phan ung = 3a - 0,09. Mol: • mc-a Bao toan khoi lugng: khoi lugng este = 15,4 + 4,6 - 11,2 = 8,8 gam J Q ^ ^ i ?, Goi so'mol trong Y : CsHb = 3a; H2 = 2a. So'mol brom phan ung = 0,09 ^^...ex M\ ly.^ (.,,.^1,1;, Khi dot chay Y thu dixqic C O 2 = 9a mol; H 2 O = 11a mol. Kho'i luong binh nude voi giam = kho'i lup-ng C a C O s - (kho'i lugng C O 2 + khoi lugng H 2 O ) —> a = 0,05 mol. Goi so'mol C u = x; A g = y. Ta c6: 64x + 108y = 2,68. Bao toan electron ta c6: 2x + y = 3 so mol N O = 0,06. Vay x = 0,025 mol; y = 0,01 mol. Khi cho tie'p 0,025 mol C u , xay ra hai phuong trinh phan ung: Hieu suat (tinh theo H2) = ^'^'^^'^'^ .100% = 60%. 3 C u + 8HNO3 > 3Cu(N03)2 + 2 N O + 4 H 2 O Mol: 0,015 Zau 30. Chon A. C u + 2AgN03- Do cac este don chuc nen so' mol K O H = tong so mol cac este, do v^y truoc -> Cu(N03)2 + 2Ag he't can tinh duoc tong so'mol este. , Mol: Nhan tha'y, phan tu cac este tren deu c6 4 nguyen tu cacbon dot chay 1 Cha't ran gom: C u = 0,005 mol; A g = 0,01 mol mol hon hop este se thu duoc 4 mol C O 2 - > tong so mol este ^ (1/4) so mol C O 2 = 0,03 mol _> the tich dung dich K O H = 0,03/0,15 = 0,2 lit = 200ml. :au31. ChgnD. 0,005 m = 0,005.64 + 0,01.108 = 1,40 gam Cau 34. Chgn B. M C O s + 2HC1 De biet y can biet so mol H N O 3 . R2CO3 + 2HC1 Mat khac: so' mol H N O 3 = so' mol NO2 = so' mol N O . 0,01 0,01 > MCI2 + CO2 + H2O 2RC1 + CO2 + H2O Ta nhan thay: so mol C O 2 = so mol H 2 O = (1/2) so mol H C l = 0,02 mol. . So moi N O phy thugc vao so mol H * va N O 3 ban dau va dugc tinh tu ban Bao toan khoi lugng: 2,42 + 0,04.36,5 = m + 0,02.44 + 0,02.18 .>f'y \m A phan ung: - > m = 2,64 gam. \, NO; (mol): 0,008 + 3e + 4H^ 0,024 0,032 > N O + 2H2O ** 192 • ^'iiri'? <{^t\ h if;;; >; Cau 35. C h o n B. liC^H":: Gia s u khoi lugng muoi trong X la 100 gam 0,008 Vay [H*] = [HNO3] = 0,008/0,8 = 0,01 if) • jr? • p H = y = 2. ' cfvr! i ' ' —> Khoi lugng muoi trong Y la 88,875 gam * » «' > giam 11,125 gam. ^ u . u . i . n i i 6D-v.; 393 Ill naiiy tin liiyrii llii ilai 1> HC CI2 + 2KBr gam: cluiyfMi (In iloa hqc - IMguygn Van H^i Cty Ti\ 11 [ i M i V DVVH Khang Vigt : giam 89 gam a Do la cac chat chua no'i doi C=C mach ho (stiren, axit metacrylic, etilen, : giam 11,125 gam 149 butadien); bi oxi hoa khi dun soi vai thuoc ti'm (toluen) v a chua nhom chuc , v. V''-^', ' 1. andehit (propanal). * ' "''I a = 29,75 g a m ^ % K B r = 29,75%. :au36.ChQnB. 4!) |Cau 42. Chon D . -» 2KC1 + Br2 238 gam: ^ 18 :au43. C h o n A •'^'"""^ ' ' ^ "" ' ^ ^ ' , -1 • 1 Trong 0,15 mol X: A l = a; Z n = b. Glucozo the hien tinh khir khi nhom chuc andehit cua glucozo tac dung voj T a c 6 : a + b = 0,15. cac chat oxi hoa. I :au 37. Chon C . So mol H2 = 0,2 ^ Vay: a = 0 , l ; b = 0,05. (1) Khong diing vi X, Y khong ciing so hieu nguyen tii: X co so hieu nguyen tu la 13; con Y la 26. 1,5a + b = 0,2. . . - > T i 1^ ve so mol A l : Z n = 2 : 1. " Trong m gam X: A l = 2x mol; Z n = x mol (2) Khong dung vi X, Z khong ciing so hieu nguyen tu. 102X-81 x = 18,3 (3) Diing vi X, Z deu ciing so khoi la 26. x = 0,l. Vay m = 0,2.27 + 0,1.65 = 11,90 gam. (4) Khong diing v i X, Y khong cung so hieu nguyen ttr: X c6 so natron la ••:!olvj ISu 44. C h o n A . ; f ,4,^ 2 6 - 1 3 = 13; con Y la 2 6 - 1 2 = 14. AI2O3 = X mol; Z n O = x mol :au38. C h o n B . I Dot chay ancol X thu dugc the tich CO2 < the tich hoi nuac K h i cho X tac dung voi AgNOs/NHa, dun nong ta c6 ti le: so mol X : so mol ->. X la ancol no - > cong thuc CnH2n+2-m(OH)m. AgNOs = 0,2 : 0,6 = 1 : 3 ^ Tu ti le the tich C O 2 : the tich hoi nuoc = 3/4 - > n = 3 X chiia 1 chuc andehit v a I H dinh vao cacbon I -> C3H^m(OH)m. mang noi ba — loai C va D . > Til-dii kien phan ung chay loai A . . , ^ V i m < n nen ta c6: :au39. C h o n B . Amino axit: 1 m = 3 —> 1 chat: glixerol. i u 45. C h o n B. H2N-CH2-CH2-COOH; CH3-CH(NH2)-COOH; CH3-NH-CH2-COOH. I De thay (3) la phan ung axit-bazo, khong phai phan u n g oxi hoa-khii' Muoi amoni: C H 2 = C H - C O O N H 4 . loai cac dap an A, C . ••JJ :au 40. Chon B. Cac chat: (1) mocphin; (2) cafein; (3) nicotin; (4) cocain v a (7) heroin. lau 41. C h o n D . • o« rwril 'mdfi f • B sai v i nhieu hop chat cpng hoa tri tan tot trong nuoc n h u H C l , NH3, -J': Loai dap an D vi (6) khong phai la phan ung oxi hoa-khu: C u O + H N O T CU(N03)2 + H2O. * A sai v i 6 trang thai ran thi cac hop chat ion each dien. : C sai v i hgp chat ion thuong c6 nhiet do nong chay, nhi^t do soi cac. D diing v i 6 trang thai nong chay, cac hop chat ion phan li thanh cac ion trai 194 3, , m = 2 - > 2 chat: propan-l,2-diol va propan-l,3-diol. Tuy nhien, do X ton tai 6 the ran 6 dieu kien thuong - > X khong the la este. da'u va c6 tinh dan dien. i I m = 1 —> 2 chat: propan-l-ol va propan-2-ol. V i X luong tinh _>. X la amino axit, muoi amoni hoac este. CH3OH,... ,...,.,:,,,„,,...,;,,,„,..„ I u 46. Cho.i D . I Goi cong thuc cac kim loai kiem la M : I 2M Mol: + 2H2O > 2M0H 0,04 + H2 0,02 I Bao toan kho'i luong: , '' ' I m +0,04.18 = 1,62 + 0,02.2 -> m = 0,94 gam. \.....A;y.'y. 395 dm nang On luy^n thi djii hpc 18 chuypn de Hoa hpe - Nguyjn Van HSi Cty C a u 47. Chon D. ;-V Twmi M i v DV\/H Khang Vi^t DE 50 2 A sai v i phenol la hop chat c6 nhom - O H dinh true tiep vac vong benzen. B sai v i phenol khong tae dung duoc voi KHCOa (vi tinh axit cua phenol liCau 1: Nho t u t u tdi d u dung dieh K O H vao dung dieh muo'i X thu dugc ket yeu hon axit eaebonie) tiia, sau do ket tiia tan dan. Day gom cac muo'i eo tinh chat gio'ng muo'i X la C sai v i hop ehat CsHsO ean phai la ancol bac 1. A. ZnCh, AlCb va Cr2(S04)3. B. AlCb, CrCh va ZnCh. D dung: CaHs-OH + (CH3CO)20 C. CuCh, Al2(S04)3 va CrCh. ' ' ' ' ' D. ZnCh, CrCb va FeCh. CHaCOO-CeHs + CHsCOOH. Cau 2: Cho cac chat tae dung voi nhau: Cau 48. Chon C. ;)ti Amino axit X eo nguon goe thien nhien _> X la a-amino axit -> lo^i phuong an A. 1. Nho t u t u toi d u dung djch K O H va dung djch ZnCh. 2. Nho tix tu dung dieh K H C O 3 vao dung dieh FeCb. * ?i Dua vao khoi luong phan t u de tinh so mol chan - > phuong an C. Cau 49. Chon C " Mol:' ik > AgBr + HNOs " 0,05 ' ^ ^ ' ^ ' ^ '' 6. Nho t u tir tdi d u dung dieh NH3 vao dung dieh FeCb. 0,05 NH3 tdi d u . Mol: 0,02 0,02 Z n + Fe^* Mol: 0,03 0,03 - c c H f-y, A. (1), (2), (3), (7). A. 5. B. 4. AS,C«, C. 3. . .<;K.,>,, r D. 6. I lEf i Cau 4: Tien hanh dien phan 100ml dung djch CuS04 (vdi d i f n eye tra) mot thdi ' 0,02 gian, thu dugc dung djch X, khoi luong dung djch giam 0,8 gam (d eatot chua cd hot khi). Them 1,68 gam hot Fe vao X, den khi phan ung hoan toan, > Zn2* + Fe thu dugc 1,24 gam kim loai. Nong do mol cua dung dieh CuS04 ban dau la 0,03 '' ' t l i + i »V, r. D. (1), (3), (6), (7). vdi dung dieh NaOH la: ' > Zn^^ + Cu _> Khoi luong chat ran khan = 136.0,08 + 127.0,03 = 14,69 gam. 50.0 mo;. Cau 3: So' dong phan cau tao mach hd cd cong thue C4H8O2 va tac dung duoc 0,06 Dung dieh Y chua: ZnCh = 0,08 mol va FeCh = 0,03 mol B. (1), (3), (5), (7). C. (1), (3), (5), (6). So mol Zn = 0,08 mol. Cac phuong trinh phan ung Zn + Cu^* , \,((m yu:^ :<..; .u.A Nhirng thi nghiem nao tao ra ket tua, sau do ket tua tan? -'^r. 0,06 vfii b :n.n . 7. Nho dung djch KCl vao dung djch AgNOs, sau do nho tiep dung dieh H i ^ u suat tong hop HBr = ^ - 1 0 0 % = 50%. > Zn^* + 2Ve^^ .^ ' 5. Nho t u t u tdi d u dung djch NH3 vao dung dieh ZnCh. Vay trong 287,85 gam nuae eua Z eo chua: 3.0,05 = 0,15 mol HBr. Zn + 2Fe^* i. 4. Nho t u t u toi d u dung djch NH3 vao dung dieh AlCb. _>. 100 gam Z CO chua: 4,05 gam HBr (0,05 mol) va 95,95 gam nvroc CauSCChpnC. 3. Nho t u t u toi d u dung dieh NH3 vao dung dieh CuS04. K --'-'^^ AgN03 + HBr Mol: 0,03 ' ; , ,- A.0,15M t * B. 0,25M C. 0,05M D. 0,20M. !au 5: Di^n phan dung djch mudi MSO4 (vdi dien cue tro) vdi cudng dg dong dien khdng ddi bang 1,5A. Sau thdi gian 1351 giay thi dirng d i f n phan, d eatot chua cd bgt khi va khd'i lugng eatot tang 0,672 gam. Cong thiic muo'i la A. CuS04. B. ZnS04. C. FeS04. D. NiS04. Cau 6: Cho day eae muo'i: KMn04, NaN03, Cu(N03)2, CaC03, KCIO3, AgNOa. So muol trong day khi nhiet phan hoan toan thi tao ra so mol khi nho hon I so'molmuoithamgiaphanungla: A. 2. 396 B.3. K^t'x.. C.4. D.5. 397 Cam iiaiiq on luyen thi dai hoc 18 chuyeri do H6a hpc - NguySri Vftn Hai Cau 7: H 6 n h o p X g o m K 2 O , K H C O 3 , BaCla va N H 4 C I , c6 so m o l bang 0,01 mol H o a tan hoan toan X vao m o t l u o n g nu-oc (du), d u n n o n g . Sau p h a n ung B. 3,850 g a m . C. 3,725 g a m . Cau 14: D a y nao sau day g o m cac k i m loai c6 cau true lap p h u o n g t a m kho'i 6 d i e u k i e n thuong? A . L i , N a , K. ; l o c ket tua, c6 can d u n g dich t h u duoc k h o i l u o n g muo'i k h a n la A . 2,235 g a m . If' Cty TNHH MTV DVVH Khang Vi§t D . 4,225 gam. C a u 8: Cho m gam h o n h o p X g o m N a v a A l vao nude t h u d u o c d u n g d i c h X B. L i , Be, A l . C. K, Ba, Ca. D . M g , A l , Fe. C a u 15: Tien h a n h cac t h i n g h i e m sau: (1) . N h o iie t u d u n g d i c h H C l vao d u n g d i c h KHCO3. ; 4,48 l i t H 2 (dktc) va 2,7 g a m chat ran k h o n g tan. Ne'u o x i hoa m g a m X can (2) . D u n g d j c h H 2 0 2 v a o d u n g d i c h K M n 0 4 (c6 mat axit H2SO4 loang). bao nhieu l i t k h i CI2 (dktc)? (3) . Sue k h i clo t o i d u vao d u n g d i c h KBr. A . 6,72 lit. , B. 5,60 lit. C. 8,96 lit. (4) . Sue k h i o z o n vao d u n g djch K I . D . 7,84 l i t . ^ ,^ ^ (5) . C h o k i m loai bac tac d u n g v o i k h i ozon. C a u 9: K h i d i e n p h a n N a C l n o n g chay 6 A . cue dirong, i o n Na+ bj oxi hoa. N h i i n g t h i n g h i e m xay ra p h a n u n g va tao thanh bot k h i la B. cue am, i o n N a * b j k h u . ' A . 2. C.4. g o m 0,05 m o l N a O H v a 0,02 m o l Ba(OH)2. T r o n Y v a o X t h u ket t u a Z v a d u n g djch T. Loc ket t u a Z, n u n g d e n k h o i l u o n g k h o n g d o i t h u duoc m g a m chat ran E. Gia t r j eua m la B.5,79. -«C. 5,17. m o t l u o n g d u N a O H , d u n n o n g t h u duoc 0,672 l i t k h i ( 0 dktc) va m gam ket }> t i i a . N u n g k e t tua ngoai k h o n g k h i den k h o i l u o n g k h o n g d o i t h u duoc 0,8 i j i , g a m chat ran. M a t khae, ne'u cho X tac d u n g v o i d u n g d i c h BaCh d u , thu , d u o c 4,66 g a m k e t tua. T o n g kho'i l u o n g chat tan t r o n g X la A . 3,73 g a m . B. 3,375 gam. C. 6,75 g a m . D . 7,65 gam. C a u 13: Cho so d o bien hoa: f> X 4-NaOH Y + CO2 + H2O , 2 k e m 6 p h a n c h i m d u o i nuoc. (4) K h i cho Fe tac d u n g v o i l u o n g d u d u n g djch A g N O s t h u duge A g ket tua va d u n g d i c h chi ehiia A g N O s va Fe(N03)2. A. 1. B.2. C.3. D.4. C a u 17: Phat bieu nao sau day sai? A . Glueozo va f r u c t o z o tac d u n g v o i H2 deu sinh ra sorbitol. B. Glueozo v a f r u c t o z o deu c6 kha nang t h a m gia p h a n u n g trang bae. C. Glueozo va f r u c t o z o la d o n g p h a n cua n h a u . D . T i n h b o t va x e n l u l o z o la d o n g phan eua n h a u . C a u 18: T r p i i 5,4 g a m bot A l v o i 17,4 g a m bot Fe304, tien h a n h phan u n g nhiet n h o m t r o n g d i e u k i e n k h o n g eo k h o n g k h i . H o a tan san p h a m ran t h u d u g e X •Al. sau p h a n u n g b a n g d u n g djch H2SO4 loang (du), t h u d u g e 5,376 l i t H2 Biet X, Y, Z la eac h o p chat ciia n h o m . X, Y, Z c6 the la A . AICI3, NaA102, A l ( O H ) 3 . B. AI2O3, NaA102, A l ( O H ) 3 . (3) D e bao v§ t a u bien l a m bang thep n g u o i ta gan vao v 6 tau n h i r n g t a m T r o n g cac phat bieu tren, so phat bieu d u n g la D.5,98..'i C a u 12: D u n g d i c h X chiia cac i o n : Fe^*, SO42-. NH4% C h . C h o X tac d u n g vol , d u o i tac d u n g cua d o n g dien m o t chieu. hoa va phat s i n h ra d o n g d i ^ n . D.5. C a u 1 1 : D u n g d i c h X g o m 0,02 m o l H C l va 0,01 m o l Al2(S04)3. D u n g dich Y A . 5,58. D. 5.^^^^ (2) Ban chat cua s u an m o n hoa hoe la phan u n g oxi hoa k h u , k i m loai b i o x i So chat t r o n g day k h i tac d u n g d u n g d i c h Ba(OH)2 d u tao ket t i i a la B.3. C. 4. (1) Ban chat eua s u d i e n p h a n la p h a n l i n g o x i hoa k h u xay ra 6 d i e n cue C a u 10: C h o d a y cac cha't: NH4CI, (NH4)2S04, Al2(S04)3, M g C h , ZnS04, AlCh, A . 2. B. 3. C a u 16: C h o cac phat bieu sau : C. cue d u o n g , n g u y e n t u N a b i oxi hoa. D . cue am, i o n C I " b i o x i hoa. .; , (dktc). H i e u suat eua p h a n u n g nhiet n h o m la i-r'hl , , ^ ' A . 60%. B.70%. C.80%. D . 90%. • Eau 19: Phat bieu nao sau day sai? C. A1(N03)3, NaA102, A l ( O H ) 3 . ' A . D u n g d i c h H F c6 the hoa tan Si02. D . AI2O3, A l ( O H ) 3 , A l C h . B. K h i cho t h e m n u o c vao o l e u m t h i n o n g d o cua axit sunfurie dan dat den 100%. 398 , , „ ^ ••vr,' „ , : : ' ' a ^ ' 3 9 9